另一个程序msg使用的文件 [英] file use by another program msg

问题描述

方法在这里，
文件名提取已成功解压缩，但是当我转到目录&时，尝试删除它，但是它说它正在被另一个程序使用，
我错过了什么?

The method is here,
The file name extract which is unziped successfully, but when i goto the directory & try to delete it,but it says it is using by another program,
what i got missing?

public static void UnZipFiles()
   {
       ZipInputStream stream = new ZipInputStream(File.OpenRead(@"c:\DoUnZip.zip"));
       ZipEntry theEntry;
       FileStream streamWriter = null;
       try
       {
           string tmpEntry = String.Empty;
           while ((theEntry = stream.GetNextEntry()) != null)
           {
               string directoryName = @"d:\extract";
               string fileName = Path.GetFileName(theEntry.Name);
               // create directory
               if (directoryName != "")
               {
               System.IO.Directory.CreateDirectory(directoryName);
               }
               if (fileName != String.Empty)
               {
                   if (theEntry.Name.IndexOf(".ini") < 0)
                   {
                       string fullPath = directoryName + "\\" + theEntry.Name;
                       fullPath = fullPath.Replace("\\ ", "\\");
                       string fullDirPath = Path.GetDirectoryName(fullPath);
                       if (!Directory.Exists(fullDirPath)) Directory.CreateDirectory(fullDirPath);
                        streamWriter = File.Create(fullPath);
                       int size = 2048;
                       byte[] data = new byte[size];
                       while (true)
                       {
                           size = stream.Read(data, 0, data.Length);
                           if (size > 0)
                           {
                               streamWriter.Write(data, 0, size);
                           }
                           else
                           {
                               break;
                           }
                       }
                   }
               }
           }
       }

推荐答案

使用File.Close()或将代码封闭在using块内，例如

Use File.Close() or enclose the code inside the using blocks like this

using(ZipInputStream stream = new ZipInputStream(File.OpenRead(@"c:\DoUnZip.zip"));){
      // do your work here
   }

尝试一下我在应用程序中使用过的代码，它可以正常工作:-

Try this code what i have used in my application and it is working fine :-

public string Zip(string ZipFileName)
    {
        try
        {
            if (!File.Exists(ZipFileName))
            {
                //lstProcess.Items.Add("File Does Not Exists.");
                return "";
            }

            using (ZipInputStream s = new ZipInputStream(File.OpenRead(ZipFileName)))
            {
                string fileName = "";
                ZipEntry theEntry;
                while ((theEntry = s.GetNextEntry()) != null)
                {
                    string directoryName = Path.GetDirectoryName(theEntry.Name);
                    fileName = Path.GetFileName(theEntry.Name);

                    // create directory
                    if (directoryName.Length > 0)
                    {
                        Directory.CreateDirectory(Server.MapPath("") + "\\XML\\" + directoryName);
                    }

                    if (fileName != String.Empty)
                    {
                        using (FileStream streamWriter = File.Create(Server.MapPath("") + "\\XML\\" + theEntry.Name))
                        {

                            int size = 2048;
                            byte[] data = new byte[2048];
                            while (true)
                            {
                                size = s.Read(data, 0, data.Length);
                                if (size > 0)
                                {
                                    streamWriter.Write(data, 0, size);
                                }
                                else
                                {
                                    break;
                                }
                            }
                        }
                    }
                }
                return fileName;
            }
        }
        catch (Exception ex)
        {
            //Display Error
            return "";
        }
        finally
        {
            //Update Status
        }
    }

调用此功能
------------------------------
字符串extractFileName = Server.MapPath(")+"\\ XML \\" + Zip(FilePath);

calling to this function
------------------------------
string extractFileName = Server.MapPath("") + "\\XML\\" + Zip(FilePath);

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