在catch块之后继续执行程序(循环). [英] Continuation of the program (loop for) after the catch block.
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问题描述
try and catch块正在循环中.
假设是当i = 2源代码传输到catch时.在catch块应从i = 3循环以继续之前
A try and catch block is in the loop for.
The assumption is when i = 2 source code is transferred to the catch. After the catch block should loop from i = 3 to continue
推荐答案
在i = 2
出现异常后,以下内容确实会继续到3和4:
The following does continue to 3 and 4 after an exception wheni = 2
:
for (int i = 1; i < 4; i++)
{
try
{
int s = 1 /(i - 2);
}
catch
{
}
}
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