如何修复Java中输入字段无法退格的错误 [英] How to fixe bug can't backspace of input field in java
问题描述
大家好，
我在webjava中遇到有关JavaScript的问题，为什么我不明白.
当用户在输入字段中输入内容时，我进行了编码以验证最大长度值，但是
我输入的字符串长度等于最大长度，并且我不能退格或删除任何字符.此问题仅在firefox上发生，IE可以.我想输入11个字符的字符串时可以退格或删除任何字符以编辑此字符串.
(使用代码javascript未设置属性)
希望您能尽快得到我的帮助.
我的代码:
Hi all,
I am having a problem about javascript in webjava that why i don''t understand.
I coded to validate max length value when user input into input field, but when
I input a string that it''s length equal max length and i can''t backspace or delete any char. this problem only happen on firefox, IE is ok. I want to when i input a string 11 chars and I can backspace or delete any char to edit this string.
(using code javascript not set properties)
I hope that I will be received help from you as soon as.
my code:
<head>
<script type="text/javascript">
$(document).ready(function() {
$("input[name='staffID']").each(function () {
$(this).keydown(function(event){
var num = ($(this).val()).toString();
// only allow to input maximum 11 digit
if(num.length > 10){
return false;
}
return true;
});
});
});
</script>
</head>
<input type="text" name="staffID" id="staffID" class="alphanum" size="8" value="${f:h(workerNumberForm.staffID)}" />
预先感谢.
Thank in advance.
推荐答案
(document).ready(function(){
(document).ready(function() {
("input [name ='staffID ']).each(function(){
("input[name='staffID']").each(function () {
(this).keydown(function(event){ var num =(
(this).keydown(function(event){ var num = (
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