构造函数ArrayAdapter＆LT;串GT;未定义 [英] The constructor ArrayAdapter<string> is undefined

问题描述

我有一个方法， initializeViews ，其中遇到的 ArrayAdapter构造未定义错误在文件的最后一行。

该方法位于 F1Fragment ，它扩展了 MainFragment 。 MainFragment 然后连接到活动。

难道我们不能给出一个片段在 ArrayAdapter＆LT上下文;串＆GT; 构造？我是新来的Andr​​oid系统。请指正。先谢谢了。

 私人无效initializeViews（RelativeLayout的contentLayout）{
    leaguesListView =（ListView控件）contentLayout.findViewById（R.id.leaguesListView）;
    progressLinear =（的LinearLayout）contentLayout.findViewById（R.id.progressLeagues）;
    值=新的String [] {RedBullRacing，迈凯轮，莲花，
      印度力量车队，HRT，​​法拉利};
    适配器=新ArrayAdapter＆LT;串GT;（F1Fragment.this，android.R.layout.simple_list_item_1，android.R.id.text1，价值观）;
}
 

解决方案

修改 F1Fragment.this 到 getActivity（）。在片段不是上下文。

I have a method, initializeViews, which encounters an ArrayAdapter constructor undefined error in its last line.

The method is located in F1Fragment, which extends MainFragment. MainFragment is then attached to an Activity.

Can we not give the context of a Fragment in the ArrayAdapter<string> constructor? I am new to Android. Please correct me. Thanks in advance.

private void initializeViews(RelativeLayout contentLayout) {
    leaguesListView = ( ListView ) contentLayout.findViewById ( R.id.leaguesListView );
    progressLinear  =   (LinearLayout) contentLayout.findViewById ( R.id.progressLeagues );
    values= new String[] { "RedBullRacing", "McLaren", "Lotus",
      "ForceIndia", "HRT", "Ferrari" };
    adapter= new ArrayAdapter<String>(F1Fragment.this, android.R.layout.simple_list_item_1, android.R.id.text1, values);
}

解决方案

Change F1Fragment.this to getActivity(). The Fragment is not a Context.

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