非十进制正整数的正则表达式，范围在0到999999之间 [英] Regular Expression for Non decimal positive integer ranging between 0 to 999999

问题描述

我需要匹配所有正非十进制整数的正则表达式，其范围从0到999999.它将不接受任何十进制，字母或任何特殊字符，范围应在0到999999之间.

I need the regular expression which matches all positive non decimal integers only range from 0 to 999999. It will not accept any decimal, alphabets or any special character and range should be in between 0 to 999999.

推荐答案

尝试以下操作:

Try the following:

\s+\d{1,6}\s+

它将为您提供1234并包含以下数据:

It will give you 1234 with the following data :

1234567
1234
abc1111

尝试以下正则表达式:^[0-9]{1,6}

Try this regex: ^[0-9]{1,6}

要对此进行测试，您可以转到以下链接:
http://www.regular-expressions.info/javascriptexample.html [

To test this you can go to below link:
http://www.regular-expressions.info/javascriptexample.html[^]

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