关于p2p客户端代码的一些知识 [英] Something about p2p clients code

问题描述

现在，我正在尝试制作有关在线视频点播的软件，使用p2p解决网络问题.
以下是错误&我找不到路...
PS:好像有点乱了...原谅我...

Now I''m trying to make a sofeware about online video on demand,use p2p to solve network question.
The following is an error & i can''t find the way...
PS: it''s seems like a litter longer... forgive me...

int Command() //get the command
{
	char key[256],temp[256];
	int i,j,result;
	char *command[6]={"connect","play","pause","stop","quit","?"};
	char parameter[256];
	printf("please input command................\n");
	while(1)
	{
		memset(key,0,256);
		memset(temp,0,256);
		memset(parameter,0,256);
		int flag=0;
		printf("%s>>",strHostName); //show the command symbol
		gets(temp);
		j=0;  //remove the excess space 
		for(i=0;i<strlen(temp);i++)>
		{
			if(temp[i+1]!='\0')
			{
				if(temp[i]==' '&&temp[i+1]==' ')i++;
				else{key[j]=temp[i];j++;}
			}
			else
			{
				if(temp[i]==' '){key[j]='\0';break;}
				else{key[j]=temp[i];j++;key[j]='\0';}
			}
		}
		key[j+1]='\0';
		i=strcspn(key," ");
		key[i]='\0';
		i++;j=0;
		while(key[i]!='\0')
		{
			parameter[j]=key[i];
			i++;j++;
		}
		parameter[j]='\0';
		
		for(i=0;i<13;i++)   //compare with the original command String       
			if(strcmp(key,command[i])==0)
			{
				flag=1;
				break;
			}
		if(flag==0)
		{
			printf("%s>>",strHostName);
			cout<<"bad command!"<<endl;
		}
		else
		{
			switch(i)
			{
			case 0:
				result=Connect(parameter);
				break;
			case 1:
				result=Play(parameter);
				break;
			case 2:
				Pause();
				break;
			case 3:
				Stop();
				break;
			case 4:
				Quit();
				exit(0);
			case 5:
				for(i=0;i<6;i++)
				{
					printf(command[i]);
					printf("\n");
				}
				break;
			}
		}
		switch(result)
		{
		case 0:
			break;
		case 1:
			printf("%s>>",strUserName);
			cout<<"parameters are not enough!"<<endl;
		case 2:
			printf("%s>>",strUserName);
			cout<<"parameters are more!"<<endl;
		}
	}
}

int Connect(LPSTR parameter)
{
	int i,j,k,len=strlen(parameter);
	char temp[10];
//////////////////////////////////////////////////parameter/////////////////////////////////////////
	if(!strlen(parameter))
		return 1;  //no parameter
	k=strcspn(parameter," ");
	parameter[k]=5;
    i=0;j=0;
	while(parameter[i]!=5)
	{
		sIP[j]=parameter[i];
		i++;j++;
	}
	sIP[j]='\0';

	k=strcspn(parameter," ");
	if(k==len)
		return 1;  // lack parameter
	parameter[k]=5;
    i++;j=0;
	while(parameter[i]!=5)
	{
		strUserName[j]=parameter[i];
		i++;j++;
	}
	strUserName[j]='\0';

	k=strcspn(parameter," ");
	if(k==len)
		return 1;
	parameter[k]=5;
    i++;j=0;
	while(parameter[i]!=5)
	{
		strPassWord[j]=parameter[i];
		i++;j++;
	}
	strPassWord[j]='\0';
    
	k=strcspn(parameter," ");
	if(k<len)>
		return 2;  //excess parameter
	i++;j=0;
	while(parameter[i]!='\0')
	{
		temp[j]=parameter[i];
		i++;j++;
	}
	temp[j]='\0';
	Port=atoi(temp);

然后打开clients.exe，无论用什么词，答案始终是参数不够用".
我对此一无所知...希望有人救我，除非我的上帝.

将标签更改为C，因为其中没有C ++.

Then open clients.exe,no matter what words,the answer always be"parameters are not enought¶meters are more "
I have no idea about it...hope someone to save me unless my god..

Changed tags to C as there''s no C++ in there

推荐答案

首先，您需要休息一下您所有的案例，除非您要执行下一个案例:

Well, to start with, you need a break in all of your cases unless you want the next case to execute:

switch(result)
{
case 0:
    break;
case 1:
    printf("%s>>",strUserName);
    cout<<"parameters are not enough!"<<endl;
    break; //if this isn't here case 2 will also run!
case 2:
    printf("%s>>",strUserName);
    cout<<"parameters are more!"<<endl;
    break; //you don't need this one, but it will prevent problems if you add more cases and forget to add it then
}

这就是为什么您同时收到两条消息的原因.两者都告诉我，您总是遇到情况1(情况0将不显示任何内容，情况2将仅显示最后一条消息).因此，调试程序并找出正在击中哪个"return 1"，然后从那里开始工作！

So that''s why you get both messages. Getting both tells me that you are always hitting case 1 (case 0 would print nothing, and case 2 would only print the last message). So debug the program and figure out which "return 1" is being hit, and work from there!

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