替换javascript变量中的函数 [英] Replace Function in javascript varable

问题描述

Hai .............



这是预见的，请给这个问题

问题是

url: http://localhost:1470/DistanceDemo/Viewmap.aspx?start = Hal，Bangalore& end =#4，64/65，第27层主楼，NIFT路，HSR布局1st班加罗尔卡纳塔克邦部门


上面的网址，我存储在Java脚本的 var 中，我使用带有 ！@#$％^ *() 等多个符号的replace函数>怎么可能


我的解决方案是var a = a. replace(！@#$％^&"，空格");


感谢

Hai.............



This is preadeep, please give this problem

Question is

url :http://localhost:1470/DistanceDemo/Viewmap.aspx?start=Hal,Bangalore&end=# 4, 64/65, Ground Floor, 27th Main, NIFT Road, H S R Layout 1st Sector Bangalore Karnataka


The above url, i am stored in var in java script, i use replace function with multiple symbols like !@#$%^*() how should possible


my solution is var a=a. replace("!@#$%^&","space");


thanks

推荐答案

％^ *() 怎么可能


我的解决方案是var a = a. replace(！@#

%^*() how should possible


my solution is var a=a. replace("!@#

％^&"，空格");


谢谢

%^&","space");


thanks

您可以使用Java中的Regex来实现.

尝试:

You can do it using Regex in Javascript.

Try:

// url is what you want to clean
var sourceString = new String(url);
var outString = sourceString.replace(/[!@#

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