与C#一样，将值排序为双值 [英] Sorting values double values as in C#

问题描述

大家好，

我已将变量声明为字符串，并在其中放置了双精度值.例如

Hi All,

I have declared a variable as string and placed double values in that. e.g.

string Numbers=string.Emtpy;
Numbers="128";
Numbers="124";
Numbers="122";
Numbers="121";
Numbers="120";
Numbers="";
Numbers="117";

现在，我想根据无值对这个变量进行排序.
我想要的结果是:

Now I want to sort this variable as on the basis of no values.
I want result as:

Numbers="";
Numbers="117";
Numbers="120";
Numbers="121";
Numbers="122";
Numbers="124";
Numbers="128";

请帮忙

Mohd Wasif

Please help

Mohd Wasif

推荐答案

不确定您是否正在寻找这个，不过请看以下CP中的文章:
以C#排序的数字字符串 [ http://www.dotnetperls.com/sort-number-strings [

Not sure if you are exactly looking for this, nevertheless have a look at below article in CP:
Numeric String Sort in C#[^]
http://www.dotnetperls.com/sort-number-strings[^]

检查此

Hi ,
Check this

string[] Numbers = new string[6];
        Numbers[0] = "128";
        Numbers[1] = "";
        Numbers[2] = "122";
        Numbers[3] = "121";
        Numbers[4] = "120";
        Numbers[5] = "117";
        var res = (from x in Numbers
                   orderby x ascending
                   select x).ToList();
        GridView1.DataSource = res;
        GridView1.DataBind();

最好的问候
M.Mitwalli

Best Regards
M.Mitwalli

那是行不通的.您的代码创建一个字符串，然后重复覆盖当前值，仅保留最终的"117"值.

而是使用列表或数组来保存多个字符串:

That isn''t going to work. Your code creates a string, then overwrites the current value repeatedly, leaving only the final "117" value.

Instead, look at using a List or an Array to hold multiple strings:

string[] arrayOfStrings = new string[] { "128", "124", "122", "121", "120", "", "117" };
Array.Sort(arrayOfStrings);

List<string> listOfStrings = new List<string>();
listOfStrings.Add("128");
listOfStrings.Add("124");
listOfStrings.Add("122");
listOfStrings.Add("121");
listOfStrings.Add("120");
listOfStrings.Add("");
listOfStrings.Add("117");
listOfStrings.Sort();

该列表更加灵活，因为您无需随时知道条目数-您可以添加更多.

The list is more flexible, as you don''t need to know the number of entries at any time - you can just add more.

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