如何确定窗口是否具有文件菜单? [英] How to determine if the window has a file menu?

问题描述

我是MFC的初学者，遇到了一个问题.

当我得到一个窗口的HWND时，如何确定该窗口是否具有文件菜单(例如File..Edit ...等).有时我们遇到带有标题栏的窗口，然后我们遇到带有标题栏和菜单栏的窗口……有时根本没有，所以我怎么能检测到这是代码.有什么办法吗?

我已经尝试使用GetWindowInfo(m_pSelectedParentWindow，&pwindowInfo);

其中m_pSelectedParentWindow是窗口的HWND，而pWindowInfo是WINDOWINFO变量.我还没有真正找到任何共同的趋势.

有任何想法吗?

I am a beginner at MFC, have come across an issue.

When I get the HWND of a window, how can I determine whether the window has a File Menu (for instance File..Edit...etc..). Sometimes we come across windows, with just a title bar, then we come across windows with a title bar and a menu bar...sometimes neither of them at all, so how can I detect this is code. Is there any way?

I have tried using GetWindowInfo(m_pSelectedParentWindow,&pwindowInfo);

Where m_pSelectedParentWindow is the HWND of the window and pWindowInfo is a WINDOWINFO variable. I haven''t really been able to find any common trends.

Any ideas?

推荐答案

是否此 [ ^ ]帮助吗?

Does this[^] or this[^] help?

使用MFC，您通常具有CWnd派生类.如果只有句柄，则可以使用CWnd::FromHandle()来获取临时的CWnd对象.

然后使用 GetMenu() [

With MFC, you usally have CWnd derived classes. If you only have the handle, you can use CWnd::FromHandle() to get a temporary CWnd object.

Then use the GetMenu() [^] function to access the menu and iterate through it and it''s sub-menus. But you should check that the window is not a child window before using GetMenu().

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