我该如何解决? [英] How can i resolve this?
问题描述
它已经做成了一个包含几个迷你游戏的应用程序.现在只有3个(
Formula I，Pacman，Tetris)，但其他小游戏也在开发中.
每个用户都可以玩迷你游戏，系统会跟踪分数
以及每个迷你游戏的最后一场游戏的日期.屏幕
主要显示上一个游戏日期的用户列表及其得分
进行了:
用户公式I Pacman Tetris
点数最后一场比赛点数最后一场比赛点数最后一场比赛
Paolo89 10:00:01 10/5/2012 12400 10/5/2012 192000 4/4/2012
朱利亚7:00:01 11/7/2011 17800 14/5/2011 340000 3/5/2011
我需要创建一个小的类库来管理用户.特别是
需要以下功能:
-插入/删除/修改用户
-消除所有用户
-插入/修改特定迷你游戏中给定用户的得分
-按特定迷你游戏的排名分数顺序生成
-管理两种类型的用户和来宾注册.来宾用户将
仅与昵称相关联，注册用户还取消了"anagrafica"(姓名，姓氏，
年龄...)
只需在
中实现其实现即可开发类图
任何面向对象的语言.
不必开发有关将信息保存到文件或
的部分
数据库或管理GUI的一部分.
It ''was made an application that contains several minigames. Right now they are only 3 (
Formula I, Pacman, Tetris) but are under development other mini-game.
Each user can play with the mini-game and the system will keep track of scores
and the date of the last game made for each mini-game. The screen
Main display the list of users with their scores on the dates of the last game
carried out:
User Formula I Pacman Tetris
Points Last Match Points Last Match Points Last Match
Paolo89 10:00:01 10/5/2012 12400 10/5/2012 192000 4/4/2012
Giulia 7:00:01 11/7/2011 17800 14/5/2011 340000 3/5/2011
I need to create a small library of classes that manage the users. In particular, it
require the following features:
-Insertion / deletion / modification of a user
-Elimination of all users
-Insertion / modification of the score of a given user for a certain mini-game
-Generation in order of ranking score for a certain mini-game
-Management of two types of users, and Guest Register. Guest users will
associated only with the nickname, registered users also un''anagrafica (name, surname,
age ...)
It ''s enough to develop a class diagram with its implementation in a
any object-oriented language.
It is not necessary to develop the part about saving information to a file or
database or part of the management GUI.
推荐答案
请检查适用于Android的ormlite，它非常轻巧，可用于数据库操作.Internet上有很多示例.
谢谢.
Hi,
Please check the ormlite for Android,it very light weight lib for database operation.There are many example are available on internet.
Thank you.
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