我可以知道如何纠正此错误吗? [英] May i know how to correct this error?

问题描述

字符R = 110110101;
字符y =！ R;

char R = 110110101;
Char y = ! R;

推荐答案

由于char数据类型接受
单个Unicode字符，因此在您的情况下，它将仅接受单个字符1
查看链接可能对您有帮助

http://msdn.microsoft.com/en-us/library/7sx7t66b％28v = vs.71％29.aspx

As char data type accepts
A single Unicode character so it will accepts only single char in your case 1
see the link it may help you

http://msdn.microsoft.com/en-us/library/7sx7t66b%28v=vs.71%29.aspx

如果要使用二进制值110110101，请使用十六进制等效项0x1B5(或十进制437):

If you want to use the binary value 110110101 then you use the hexadecimal equivalent 0x1B5 (or decimal 437):

char R = (char) 0x1B5;

或

or

char R = (char) Convert.ToInt32( "110110101", 2 );

我不得不使用强制类型转换:这暗示char可能不是此类表达式中的最合适的类型".
注意!是逻辑非运算符，它是为boolean操作数定义的(不是您指的是~吗?).

I had to use casts: it is an hint that possibly char is not the ''most suitable type'' in such expressions.

Beware ! is the logical not operator, defined for boolean operand (did you mean ~ instead?).

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