将对象传递给泛型方法 [英] Passing an object to a generic method

问题描述

说我们有:

Say we have :

public void method<T>(T obj)
{
   // some stuff done on the obj
}

并且我们已经反序列化了一个对象，我们需要传递

And we have deserialized an object and we need to pass

object obj = CreateObject(bytearray); // serialized byte[] of object
method(obj);

现在的问题是method需要知道其工作的对象类型(内部泛型)，但是我们传递的是object，因此它将失败.但是，CreateObject方法可以确定类型，并且可以毫无问题地重新创建原始类型.

问题是:我们如何才能以某种方式将类型信息提供给method，以便它在运行时不会中断?

Now the problem is that method needs to know the object type for it to work (internal generics) but we are passing an object, so it will fail. However the CreateObject method can determine the type and it recreates the original without problem.

The question is : how can we somehow give the type information to method so it doesn''t break at runtime?

推荐答案

我想您想使用泛型语法传递类型.如果是这样，您可以使用以下方式传递它:

Hi,
I presume you want to pass the type using the Generics syntax. If so, you can pass it using something like this:

Int32 iObj=0;
method<int32>(iObj);

或

or

Stack sObj = new Stack();
method<stack>(sObj);

我不确定您的观点是否是将类型发送到方法"方法的另一种方法?

干杯

I''m not sure if your point is another mean of sending type to the ''method'' method?

Cheers

找到的解决方案是:

Found the solution as :

object obj = CreateObject(bytearray);

var mi = this.GetType().GetMethod("method", BindingFlags.Instance | BindingFlags.NonPublic);
var m = mi.MakeGenericMethod(new Type[] { obj.GetType() });
m.Invoke(this, new object[] { obj }); // instead of method(obj);

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