仅使用XAML无法将焦点设置在Popup中的控件上 [英] unable to set focus on a control in Popup by using XAML only

问题描述

嗨

我已经在资源文件中定义了Popup控件的样式，并在UserControl中定义了Popup本身.

现在我想当我的弹出窗口被加载时，焦点应该放在弹出窗口的弹出窗口内容中包含的按钮上.

我只想在XAML中这样做.

以下是我的代码:

Hi

I have defined the style for a Popup control in my resource file and Popup itself in a UserControl.

Now i want that when my pop is Loaded the focus should be on the Button contained in the Popup Content of Popup

I want to do it in XAML only.

Below is my code:

<Style x:Key="myContentStyle" TargetType="{x:Type ContentControl}">
         <Setter Property="Template">
             <Setter.Value>
                 <ControlTemplate>
 
                <Button x:Name="DoneButton"
                                     HorizontalAlignment="Right"
                                     Grid.Row="4"
                                     Width="Auto"
                                     Margin="4,4,4,4"/>
 
        <ControlTemplate.Triggers>
                         <DataTrigger Binding="{Binding Path=IsOpen,RelativeSource={RelativeSource AncestorType=Popup}}" Value="True">
                            <Setter TargetName="DoneButton" Property="FocusManager.FocusedElement" Value="{Binding ElementName=DoneButton}" />
                         </DataTrigger>
                 </ControlTemplate.Triggers>
 
                </ControlTemplate>
             </Setter.Value>
         </Setter>
     </Style>
 




<!-- Embedded popup -->
 <Popup Style="{DynamicResourcemyPopupStyle}" > 
<ContentControlStyle="{DynamicResourcemyContentStyle}"/>
 
</Popup>

当我按下"Tab"按钮时，焦点仍然位于背景"窗口控件上.

任何帮助!!

when i press the Tab button Focus is still on the Background windows controls.

Any help !!

推荐答案

很抱歉，这是正确的解决方法

首先为边框创建样式:

I am sorry this is the right solution

first create a style for the border:

<style x:key="borderStyle" targettype="{x:Type Border}" xmlns:x="#unknown">
    <eventsetter event="Loaded" handler="OnBorderLoaded" />
</style>

然后在后面的代码中创建逻辑:

then create your logic in the code behind:

private void OnBorderLoaded(object sender, RoutedEventArgs e)
{
    var border = sender as Border;
    if (border != null)
    {
        border.Child.Focus();
    }
}

创建您的弹出样式并使边框采用较早的样式:

the create your popup style and make the border take the earlier style:

<style x:key="myPopupStyle" targettype="{x:Type Popup}" xmlns:x="#unknown">
    <setter property="Child">
        <setter.value>
            <border background="White" style="{StaticResource borderStyle}">
                <button name="DoneButton" content="Done Button">
                             HorizontalAlignment="Right"
                             Grid.Row="4"
                             Width="Auto"
                             Margin="4,4,4,4">
                </button>
            </border>
        </setter.value>
    </setter>
</style>

最终使您的弹出窗口具有正确的样式:

finally make your popup and give it the right style:

<popup style="{StaticResource myPopupStyle}" grid.row="1" />

据我所知，无法使用可用的控件来做到这一点.

如果您愿意构建一个简单的控件，我将继承PopUp表单，并捕获OnOpen事件并设置焦点.获取焦点的控件将由依赖项属性设置.

另一种选择是创建一个行为基本相同的行为.在这种情况下，执行此操作的bahavior属性将成为获得焦点的控件.

As far as I know there is no way to do this with available controls.

If you are willing to build a simple control, I would inherit form PopUp, and catch the OnOpen event and set the focus. The control to get focus would be set by a dependency property.

Another option is to create a bahaviour which basically does the same thing. In this case the bahavior property to do this would be the control to get focus.

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