[JAVA]方法将F转换为C [英] [JAVA] Method convert F to C

问题描述

大家好，我又遇到另一个问题，我收到-0.0 20次，实际上是19次，即使我需要20次

Hello everyone, I am back yet with another question, I receive -0.0 20 times, well actually 19 , even though I need 20

double temp=20;

    for(int index = 1; index < temp; index++)
    {
    celsius(index);
    }
}
public static double celsius(double temperature)
{
    double celsius;

    celsius = (5/9) * ( temperature - 32);
    System.out.println(celsius);
    return celsius;
}

推荐答案

这是因为5/9不正确.这是整数除法，当分子小于分母时始终返回0.

如果仅更改乘法顺序，则第一个整数操作数将隐式转换为double；否则，将转换为double.然后将所有其他操作数转换为double，因为第一个操作数temperature被声明为double；您会得到正确的结果:

This is because 5/9 is incorrect. This is integer division, always returns 0 when a numerator is less than denominator.

If you simply change the order of multiplication, first integer operand will implicitly convert to double; and then all other operands will be converted to double, as the first operand temperature is declared double; and you will get a correct result:

celsius = (temperature - 32) * 5 / 9;

请参阅: http://en.wikipedia.org/wiki/Celsius [

See: http://en.wikipedia.org/wiki/Celsius[^].

—SA

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