从代码获取对静态资源的子控件 [英] Get child control of Static Resource from code

问题描述

大家好，

例如，我有以下XAML

Hi guys,

For example I have the following XAML

<Window x:Class="WpfApplication1.MainWindow"

        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"

        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"

        Title="MainWindow" Height="350" Width="525">
    <Window.Resources>
        <Grid x:Key="testResource">
            <TextBox Name="txtTest" Text="test"></TextBox>
        </Grid>
    </Window.Resources>
    <Grid>
        <Frame Height="100" VerticalAlignment="Top"  Content="{Binding Source={StaticResource ResourceKey=testResource}}" />
        <Button Height="20" Name="btnTest" Content="Test" Click="btnTest_Click" />
    </Grid>
</Window>

我知道如何获取Grid x:Key="testResource":

I know how to get Grid x:Key="testResource":

Grid grid = this.FindResource("testResource") as Grid;

但是如何找到txtTest控件?

我只发现了这样的东西:

But how can I find txtTest control?

I figured out only something like this:

using System.Windows;
using System.Windows.Controls;

namespace WpfApplication1
{
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
        }

        private void btnTest_Click(object sender, RoutedEventArgs e)
        {
            Grid grid = this.FindResource("testResource") as Grid;

            foreach (UIElement item in grid.Children)
            {
                if (item as TextBox != null)
                {
                    MessageBox.Show((item as TextBox).Text);
                }
            }
        }
    }
}

有什么正确的方法吗? grid.FindName("txtTest")不起作用.

is there any right method to do it? grid.FindName("txtTest") doesn''t work.

推荐答案

您好，您可以按这样的名称查找它；

Hi, you can look it up by name like this;

Grid grid = this.FindResource("testResource") as Grid;
var myTextBox = grid.Children.Cast<UIElement>().
   Where(el => ((string)el.GetValue(FrameworkElement.NameProperty)) ==    "txtTest").SingleOrDefault();

希望这会有所帮助，
弗雷德里克(Fredrik)

Hope this helps,
Fredrik

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