反序列化XML以使用自动生成的属性进行分类 [英] Deserialize XML to class with auto generated properties

问题描述

我有一个Windows服务，该服务将侦听通过HTTP发送到Windows服务的XML数据包.我想创建一个具有基于xml属性的类.让我们假设我收到了以下xml:

I have a Windows service that will be listening for XML packets being sent over HTTP to the windows service. I want to create a class with properties based on the xml. let us assume I received the following xml:

<persondetails>
   <name>abc</name>
   <surname>def</surname>
   <age>22</age>
</persondetails>

我希望能够反序列化此xml以基于此信息创建新的类，或者只是反序列化此xml为可以访问属性的对象.

该类需要根据收到的每个xml创建，因为它们会有所不同，因此我无法创建一个类，而只能将其反序列化为typeof类.

我查看了xsd工具，但仅在命令提示符下找到了使用此工具的示例.我需要自动完成此操作，而无需任何用户交互.

i want to be able to deserialize this xml to create a new class based on this information, or just deserialize this xml into an object where I can access the attributes.

The class needs to be created according to every xml received, since they will differ, so I can''t create a class and just deserialize this to the typeof class.

I looked at xsd tool, but only found examples where working with this in the command prompt. I need it to be done automatically, without any user interaction.

推荐答案

我已经使用ExpandoObject在过去的项目中做到了这一点.

类似的东西:

I have used the ExpandoObject to do exactly this in a past project.

something like:

dynamic personDetails = new ExpandoObject();

var personLookup = (IDictionary<string, object>)personDetails;
personLookup["Name"] = yourXmlValue;

我在这里排除了XLinq，但是您应该了解要点.

然后，您可以传递动态对象，并像常规属性一样对其进行访问:

即

I''ve excluded the XLinq here, but you should get the gist.

You can then pass the dynamic object around and just access it like regular properties:

i.e.

var name = personDetails.Name;

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