如何在给定的包含空格b/n的字符串中找到最大的子字符串. [英] how to find the largest substring in a given string containing spaces b/n them.

问题描述

如果我的字符串是:如何找到最大的子字符串"
我的输出应该是:子字符串中最大的是->子串

我已经创建了一个过程，它可以正常工作，但是在字符串的末尾需要一个空格.
在此先感谢您是否建议任何可以覆盖此过程的过程以获取所需的输出.

If my string is: "hi how to find the largest substring"
My output should be: The largest of the substring is--> substring

I have created a procedure, it works fine but it requires a space at the end of my string.
Thanks in advance if u suggest any procedure that could override this procedure to get the required output.

alter procedure largerSubstring @baseString varchar(250)
AS
begin
	declare @subString varchar(max),@len int,@largestSubString varchar(max),@prevLength int,@originalLength int
	set @prevLength=0
	set @originalLength=len(@baseString)
	while(@originalLength>0)
	BEGIN
		set @subString=left(@baseString,charindex(' ',@baseString)-1)
		if(len(@subString)>@prevLength)
		begin
			set @prevLength=len(@subString)
			set @largestSubString=@subString;
		end	
		set @baseString=substring(@baseString,charindex(' ',@baseString)+1,@originalLength)

		set @originalLength=@originalLength-(len(@subString)+1)
	END
	print 'the largest string length is--> '+convert(varchar,@prevLength)
	print 'the largest susstring is-->'+@largestSubString
end

推荐答案

试试这个

Try this

alter procedure largerSubstring
    @baseString varchar(250)
AS
begin

    declare @subString          varchar(max),
            @len                int,
            @largestSubString   varchar(max),
            @prevLength         int,
            @foundIndex         int
    
    set @baseString         = isnull(rtrim(ltrim(@baseString)),'')
    set @prevLength         = 0
    set @largestSubString   = @baseString
    
    while(len(@baseString)>0)
    begin
        set @foundIndex = charindex(' ',@baseString)
        if @foundIndex = 0 -- not found
            begin
            set @subString  = @baseString
            set @baseString = ''
            end
        else
            begin
	    set @subString  = left(@baseString,@foundIndex-1)
	    set @baseString = ltrim(right(@baseString,len(@baseString)-@foundIndex))
            end

	 if(len(@subString)>@prevLength)
	   begin
	   set @prevLength         = len(@subString)
	   set @largestSubString   = @subString;
	   end	
    end
    print 'the largest string length is--> '+convert(varchar,@prevLength)
    print 'the largest susstring is-->'+@largestSubString

end

这是另一个版本，

Hi,

Here is the another version,

CREATE PROCEDURE [dbo].[usp_GetLengthyString] 
(   
 @sInputString VARCHAR(8000) 
) AS
BEGIN
DECLARE @sItem VARCHAR(8000)
DECLARE @lengthyString VARCHAR(8000)
DECLARE @sDelimiter VARCHAR 
SET @sDelimiter = ' '
DECLARE @List TABLE (string VARCHAR(8000), leng INT)
WHILE CHARINDEX(@sDelimiter,@sInputString,0) <> 0 
BEGIN 
	SELECT  @sItem=RTRIM(LTRIM(SUBSTRING(@sInputString,1,CHARINDEX(@sDelimiter,@sInputString,0)-1))), 
			@sInputString=RTRIM(LTRIM(SUBSTRING(@sInputString,CHARINDEX(@sDelimiter,@sInputString,0)+LEN(@sDelimiter),LEN(@sInputString))))
	IF LEN(@sItem) > 0 
		INSERT INTO @List 
		SELECT @sItem, LEN(@sItem)
END
IF LEN(@sInputString) > 0 
	INSERT INTO @List 
	SELECT @sInputString, LEN(@sInputString) -- Put the last item in

SELECT @lengthyString = string FROM @List ORDER BY leng ASC

PRINT 'The longest sub string is ' + @lengthyString

END

嘿，
如果U在字符串末尾需要空格，然后按Alt + 255，则插入空白字符.
祝你好运

Hey,
if U Need Space at end of string then press Alt+255 it inserted blank Character.
Good Luck

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