通过AJAX调用Web服务 [英] Calling Webservice through AJAX

问题描述

下面的代码即时通讯在我的解决方案中使用，但是当我在ajax调用中传递数据"参数时，即时通讯收到错误，但没有数据"参数，则工作正常.

谁能告诉我this.quick的反应出了什么问题.


var strInput =";
var strSearchType = $(''#ddnSearchType'').val();

strInput = strInput +''strSearch'':''" + strSearchType +''";

disableButtons();

//清除以前的结果
$("table#tblInfo tbody tr").remove();

//对JSON的Ajax调用
$ .ajax({
类型:"POST"，
contentType:"application/json; charset = utf-8"，
网址:"widgetJosn.asmx/PerformSearch"，
数据:"{" + strInput +}"，
dataType:"JSON"，
成功:parseData，
错误:AjaxFailed
});

Hi,
the below code im using in my solution, but when i pass ''data'' parameter in ajax calling, im getting the error but without ''data'' parameter it''s working fine.

can anyone tell me whats wrong with this.quick response appreciated.


var strInput="";
var strSearchType=$(''#ddnSearchType'').val();

strInput = strInput +"''strSearch'':''"+strSearchType+"''";

disableButtons();

//Clear previous results
$("table#tblInfo tbody tr").remove();

//Ajax Call to JSON
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: ''widgetJosn.asmx/PerformSearch'',
data: "{"+strInput+"}",
dataType: "JSON",
success: parseData,
error: AjaxFailed
});

推荐答案

(''#ddnSearchType'').val();

strInput = strInput +''strSearch'':''" + strSearchType +''";

disableButtons();

//清除先前的结果

(''#ddnSearchType'').val();

strInput = strInput +"''strSearch'':''"+strSearchType+"''";

disableButtons();

//Clear previous results

("table#tblInfo tbody tr").remove();

//Ajax调用JSON

("table#tblInfo tbody tr").remove();

//Ajax Call to JSON

.ajax({
类型:"POST"，
contentType:"application/json; charset = utf-8"，
网址:"widgetJosn.asmx/PerformSearch"，
数据:"{" + strInput +}"，
dataType:"JSON"，
成功:parseData，
错误:AjaxFailed
});

.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: ''widgetJosn.asmx/PerformSearch'',
data: "{"+strInput+"}",
dataType: "JSON",
success: parseData,
error: AjaxFailed
});

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