需要Json方法返回一个View或PartialView，... [英] Need Json method to return a View or PartialView,...

问题描述

您好，朋友们可以请我为我的问题提供解决方案吗，...

我正在开发mvc3剃须刀应用程序，

我有myaccount详细信息页面，其中包含不同的详细信息块，例如

名称:在此块下，名字，姓氏
地址:地址1,2，城市，邮编，...
许可证:编号，有效期，签发国家..

所以每当我编辑任何块时，我都不希望页面刷新，所以使用jquery，ajax和json方法，但是，我的问题是

Hi frnds can any one please advice me a solution to my problem,...

i''m working on mvc3 razor apps,

i have myaccount details page which consists of different blocks of details like,

Name: under this block, first name, last name
address: address 1,2,city state, zip,...
license: number,expiry,issue country..

so whenever i edit any block i don''t want page to getting refresh,so using jquery, ajax and json methods but, my problem is

[JsonException]
      public JsonResult AccountDetailsUpdate(MyDetailsModel mydetailsmodel)
      {
        return View("viewname");
      }

但它引发了我错误，无法将JsonResult转换为ViewResult
我想从json方法返回视图，我们如何使其变为

but it throws me error, unable to convert JsonResult to ViewResult
i want to return to a view from json method, how can we make it

推荐答案

您正在返回视图.那不是JsonResult.错误是告诉您返回Json，因为您说过会. 此 [

You''re returning a view. That is not a JsonResult. The error is telling you to return Json, because you said you would. This[^] shows how to return Json, the short version is

return Json(xxx)

where xxx can be a list, I usually end up returning an anonymous class like return Json(new { MyResult = true, MyValue = myVar } );, etc.

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