在c#.net中根据原因显示问题 [英] Show Question according Couse in c#.net
本文介绍了在c#.net中根据原因显示问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
嗨..朋友,我有一个表,其中有两列Course_Name和Question_Name,具有
喜欢
Hi.. Friends I have a table having two column course_Name and question_Name having
like
course_Name question_Name
ASP.Net What is ASP .Net ?
ASP.Net What is State Management ?
ASP.Net What is Session ?
Java Difference Between Java & ASP.net ?
Java Is here multiple inheritance in Java ?
我想在default.aspx页面上显示结果..
I wants to display result on my default.aspx page..
ASP.Net
What is ASP .Net ?
What is State Management ?
What is Session ?
Java
Difference Between Java & ASP.net ?
Is here multiple inheritance in Java ?
有谁请帮助我,如何使用asp.net中的任何控件来获取此信息.
请帮帮我.
谢谢&问候
Parveen Rathi
is anybody please help me how can I get this, using any control in asp.net.
Please help me.
Thanks & Regards
Parveen Rathi
推荐答案
如果您的页面只有两个课程名称,则可以使用以下两个查询
If your page has only two course names you can use following two queries
SELECT question_Name FROM TableName WHERE course_Name="Asp.Net"
SELECT question_Name FROM TableName WHERE course_Name="Java"
否则,您可以使用单独的方法来获取以下格式化的输出
otherwise you can use separate method to get following formatted output
string[] s= (FROM TableName SELECT DISTINCT course_name);
//linq code for retrieve distinct courses
foreach(str in s){
getOutput(str);
}
string getOutput(string course){
string output=course+"\n";
string[] s=(FROM TableName
WHERE course_Name=course
SELECT question_Name);
foreach(str in s){
output+=str+"\n";
}
return output;
}
这不是确切的代码,但希望您能从中获得一些想法...
This is not exact code but hope you can get some idea from this...
检查此 ^ ]
您可以使用LINQ组联接.见下面的链接
http://social.msdn.microsoft.com /forums/zh-CN/linqprojectgeneral/thread/e6fcc00c-1f2a-4f29-9d7e-32f14323cb5a/ [ http://www.dotnetlogix.com/article/LINQ/111/Group- join-in-LINQ.html [ ^ ]
You can use LINQ group join. See below links
http://social.msdn.microsoft.com/forums/en-US/linqprojectgeneral/thread/e6fcc00c-1f2a-4f29-9d7e-32f14323cb5a/[^]
http://www.dotnetlogix.com/article/LINQ/111/Group-join-in-LINQ.html[^]
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