需要从tblcolmn中查找时间,其中时间少于当前时间2小时 [英] Neeld to find time from a tblcolmn where time is less than 2 hours before the current time
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问题描述
我有一个名为tblactivity的表,其中有一个称为checkintime的列.
现在,我需要查找所有在当前时间的最后2小时内的签到时间.
Hi,
I have a table called tblactivity,where there is a column called checkintime.
Now I need to find all the checkin time which is within last 2 hours of the current time.
thanks in advance.
推荐答案
请尝试此查询...
TRY THIS QUERY...
SELECT * FROM tblactivity where DATEDIFF(hour,checkintime,GETDATE()) <= 2
希望它能帮助...
HOPE IT HELPS...
在查询后检查
check following Query
SELECT * FROM tblactivity WHERE checkintime BETWEEN DATE_SUB(NOW(), INTERVAL 2 HOUR)
这里是:
Here it is :
select * from tblactivity where checkintime > DATEADD(HOUR, -2, GETDATE())
祝你好运
Good Luck
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