等效于C#的位集翻转方法 [英] C# Equivalent of bitset Flip method

问题描述

我有一个需要翻转的BitArray.在C ++中，您可以仅使用以下语法:

I have a BitArray which I need to flip. In C++ you can just use the following syntax:

bitset<5> MyBitset (mystring);
MyBitset.flip();

如何在C#中获得相同的结果?另外，我现在需要获取此位集(好吧，在C#中为BitArray)并将其转换为双精度型.在C ++中，我只能使用.to_ulong()方法，但是C#没有给我该选项:/

任何帮助都会很棒！

预先感谢.

How can I achieve the same result in C#? Also, I now need to take this bitset (well, BitArray in C#) and convert it to a double. In C++ I can just us the .to_ulong() method, however, C# does not give me that option :/

Any help will be awesome!

Thanks in advance.

推荐答案

使用BitArray类的Not()方法.

这是有关BitArray的信息的链接
http://msdn.microsoft.com/en-us/library/system.collections. bitarray.aspx [ ^ ]
您可能想查看BitConverter类，也许可以帮助将BitArray转换为double.

Use the Not() method of the BitArray class.

Here is a link for info about BitArray
http://msdn.microsoft.com/en-us/library/system.collections.bitarray.aspx[^]
Edit 2: You may want to check out the BitConverter class maybe it can help to convert BitArray to double.

这篇关于等效于C#的位集翻转方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！