C#-NetDuino-串行 [英] C# - NetDuino - Serial

问题描述

你好

我需要一些代码帮助，因为我一直在重新排列它并添加内容并使用try，catch，但是无论我尝试什么，我都无法使串行与Netduino上的伺服/PWM一起使用.

此代码将写入Netduino，并且Netduino将对串行作出响应，但是一旦冻结，它就会冻结.

请任何帮助将不胜感激.

谢谢

问候
米切尔

代码:

Hello

I need some help with my code because i keep re-arranging it and adding stuff and using try, catch but no matter what i try i cannot get the serial to work with a servo / PWM on Netduino.

This code writes to the Netduino and the Netduino responds on serial but as soon as the while begins it freezes.

Please any help would be appreciated.

Thanks

Regards
Mitchell

CODE:

using System;
using System.Threading;
using Microsoft.SPOT;
using Microsoft.SPOT.Hardware;
using SecretLabs.NETMF.Hardware;
using SecretLabs.NETMF.Hardware.Netduino;
using System.IO;
using System.Text;
using System.IO.Ports;

namespace mrinc
{
    public class Program
    {
        static SerialPort port = new SerialPort("COM1", 9600, Parity.None, 8, StopBits.One);
        static PWM servo = new PWM(Pins.GPIO_PIN_D5);
        static int[] range = new int[2];
        static byte[] buffer = new byte[32];
        public static void Main()
        {
            initializeSerial();
            initializeServo();
            s = "M.R. Inc*******";
            port.Write(Encoding.UTF8.GetBytes(s), 0, s.Length);
            while (true)
            {
                int count = 0;
                try { count = port.Read(buffer, 0, buffer.Length); }
                catch (Exception) { }
                if (count > 0)
                {
                    char[] c = Encoding.UTF8.GetChars(buffer);
                    if (c[0] == '1')
                    {
                        setServo(0);
                    }
                    if(c[0] == '0')
                    {
                        setServo(90);
                    }
                }
            }
            private static long map(long x, long in_min, long in_max, long out_min, long out_max)
        {
            return (x - in_min) * (out_max - out_min) / (in_max - in_min) + out_min;
        }
        private static void setServo(int value)
        {
            try
            {
                servo.SetPulse(20000, (uint)map((long)value, 0, 180, range[0], range[1]));
            }
            catch (Exception)
            { }
        }
        private static void initializeServo()
        {
            range[0] = 1000;
            range[1] = 2000;
            servo.SetDutyCycle(0);
            setServo(90);
        }
        private static void initializeSerial()
        {
            port.ReadTimeout = 0;
            port.Open();
        }

推荐答案

它冻结，因为您正在执行阻塞Read调用，并将超时设置为零.这意味着在读取Buffer.Length字符之前，Read将不会返回-错误超时已被您写入的零禁用.如果Arduino没有至少提供Buffer.Length字符，则.读取将永远不会返回.

查看更改为事件驱动的读取:使用 SerialPort.DataReceived事件 [ ^ ]收集每个字符，并在缓冲区中建立它提供的任何消息.至少以这种方式，您可以查看接收到的内容，并有更好的机会调试数据流.

It freezes because you are doing a blocking Read call , having set the timeout to zero. That means that the Read will not return until Buffer.Length characters have been read - the error timeout has been disabled by the zero you wrote to it. If te Arduinoi does not supply at least Buffer.Length characters,. Read will never return.

Look at changing to an event driven read: use the SerialPort.DataReceived Event[^] to collect each character as it comes, and build up whatever message it provides in a buffer. At least that way you can look at what is being received and stand a better chance of debugging the dataflow.

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