如何动态分配通用类型 [英] How to dynamically assign generic Type

问题描述

通用类:

Generic class:

public class GenericEntityMapping
{
    public T Map<t>(XmlNode xNode, T entityObject)
    {
        //FYI.
        //PropertyInfo[] entityProperties = typeof(T).GetProperties();
        //foreach (PropertyInfo pInfo in entityProperties){...}

        //somewhere in the code depends on the condition.
        if true then...
        GenericEntityMapping<SampleEntity01>.Map(node, new SampleEntity01())
        .
        .
        .
        else if true then...
        GenericEntityMapping<SampleEntity02>.Map(node, new SampleEntity02())
    }
}

在通用类型不需要硬编码的情况下，我该怎么办?


我的目标是这样的:
类型myType = pInfo.PropertyType.GetType();
GenericEntityMapping< myType> .Map(node，System.Activator.CreateInstance< myType>());

How can i do it where the type in the generic needs not to be hardcoded?


My goal is something like:
Type myType = pInfo.PropertyType.GetType();
GenericEntityMapping<myType>.Map(node, System.Activator.CreateInstance<myType>());

Is it possible?

推荐答案

对于类型，泛型和开始静态不相关.泛型和非泛型类型都可以是静态的，也可以不是静态的.

—SA

For a type, being generic and begin static are not related. Both generic and non-generic types can be static or not static.

—SA

你好SAKryukov，
感谢您的快速回复.

我找到了解决方法:

Hello SAKryukov,
Thanks for the quick reply.

I found the solution:

MethodInfo method = typeof(GenericEntityMapping).GetMethod("Map");
MethodInfo generic = method.MakeGenericMethod(Type.GetType(pInfo.PropertyType.FullName));

object[] objParam = { node, System.Activator.CreateInstance(Type.GetType(pInfo.PropertyType.FullName)) };
pInfo.SetValue(entity, generic.Invoke(this, objParam), null);

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