为什么它不起作用? [英] why it does not work?

问题描述

echo (true?''true'':''t''); //it''s wrong......why???

推荐答案

这当然应该评估为''true''.

它应该(并且确实)打印字符串"true".
如果您希望这样做，则需要查看 ^ ].

It should (and does) print the string "true".
If you expect it to do otherwise, then you need to look at the PHP ternary operator[^] in more detail.

您的注释中的错误消息表明echo之前的行缺少分号(;).

;在PHP中不是可选的.

The error message in your comment suggests that the line before the echo is missing a semi-colon (;) at the end of it.

The ; is not optional in PHP.

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