C#中的逻辑运算符 [英] logical Operators in C#

问题描述

嗨 下面的代码应返回15，但在C#中返回值为14！
为什么在C#中返回值为14

  int  x =  2 ;
 int  y = x + 4 * ++ x;
MessageBox.Show(x.ToString()+ "  + y.ToString());

解决方案

14是正确的

对于左侧，x = 2 + 4 *(x = 3增量) 2+ 4 * 3-> 14

Mehdi和Abhinav是正确的.
Java中的结果也是14.
等同于y = x + 4 *(x + = 1);

表达式从左到右求值.
如果将左边的x移到右边，您将得到15，y = 4 * ++ x + x;

int y = x + 4 * ++ x;
可以简化为y = x + 4 *(x + 1).

++ x是前缀一元运算符.因此，首先添加1，然后将其用于进一步的计算.
结果，表达式变成2 + 4 *(2 +1)，因此变成14.

hi The under code should return 15 but in C# return value is 14 !!!
why in C# return value is 14

int x = 2;
int y =x+ 4* ++x;
MessageBox.Show(x.ToString()+"\n"+y.ToString());

解决方案

14 is correct

For the left x=2 + 4 * (increment x =3) -> 2+ 4*3 -> 14

Mehdi and Abhinav are correct.
The result is also 14 in Java.
It is identical to y = x + 4 * (x+=1);

The expressions are evaluated left to right.
You will get 15 if the left x is moved to the right, y = 4 * ++x + x;

int y =x+ 4* ++x;
This can be simplified to y = x + 4 * (x+1).

++x is a prefix unary operator. So the 1 is first added and then it used for further calculation.
As a result expression becomes 2 + 4 * (2 + 1) and hence 14.

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