将字母字符串转换为ASCII码，然后再次返回 [英] Alphabet String to ASCII codes and back again

问题描述

大家好，

我正在尝试将大写字母字符的短字符串转换为相应的ASCII代码(或者是否有更好的方法来获取字符串，因为数字请告诉我).

我想要的是输入大约9个字符的字符串，让它将字符串中的每个字符转换为数值(其中A = 1，B = 2等)，以便我可以对其进行一些检查，并附加另一个数字放在末端，然后再次将其吐出为一串字母.

这是出于检查数字的目的，因此在程序的后面，我还想重新计算该检查数字，并将其与新字符串上附加的数字进行比较.

如果没有那么复杂的方法，请提出建议！

感谢

Hi guys,

I''m trying to convert a short string of uppercase alphabetical characters to the corresponding ASCII codes (or if there''s a better way to get the string as numbers let me know please).

What I want is to feed in the string of around 9 chars, have it convert each char in the string to a numerical value (where A=1, B=2 etc) so that I can perform some checks on it, append another number onto the end and spit it back out as a string of letters again.

This is for the purpose of a Check Digit, so later in the program I also want to recalculate the Check Digit and compare it to the appended one on the new string.

If there''s a less convoluted way to do this please suggest!

Thanks

推荐答案

您可以从Unicode代码点值创建校验和，因此:

You can create a checksum from the Unicode code point value thus:

int sum = 0;
foreach(char c in s) sum += (int)c;

如果希望它以A = 1开头，则执行sum += (1 + c - ''A'').

If you want it to start with A=1 then do sum += (1 + c - ''A'').

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