使用AT命令打开TCP端口? [英] open tcp port using AT Command?

问题描述

如何使用GPRS在AMOD GSM设备上打开TCP端口?

我能够通过一些端口号将数据从我的AMOD GSM设备发送到某个静态IP服务器.

AT + AIPO = 1 ,," 14.97.98.47，8080,0
服务器ip = 14.97.98.47
端口8080


工作(可以发送数据):
来自设备=>到服务器

不起作用:
从服务器=>到GSM设备(在某些特定端口)

如何在GSM设备上打开端口，以便服务器可以发送数据.


类似的东西:

AT + AIPO = 1,10000，"14.97.98.47"，8080,0

因此，在10000端口上，我们从服务器监听数据.调制解调器模块.通过使用ACM8068，您可以在M2M，移动语音/数据和公用电话应用程序中提供世界一流的性能.
ACM8068具有无与伦比的四频RF性能和灵敏度，从而扩大了GSM网络的覆盖范围，并减少了掉话的次数.将语音和数据通信集成到各种应用程序中时，ACM8068为用户提供了更高的灵活性，并缩短了产品上市时间.

ACM8068由AT命令控制，并带有AT/Telecom命令中间件，使用户能够拥有易于使用的解决方案和高度可靠的调制解调器，从而缩短了设计周期并简化了工作.

http://www.amod.com.tw/Product/product_more.asp?vrlSholMe7iBxJO2wrpSmKiig+ /a> [^ ]

how can i open TCP Port on AMOD GSM device using GPRS?

i am able to send data from my AMOD GSM Device to some static ip server with some port no.

AT+AIPO=1,,"14.97.98.47",8080,0
server ip =14.97.98.47
port 8080


Working(can send data ):
From Device => To Server

NOT Working :
From Server => To GSM Device (at some specific port)

how can i open a port on GSM Device so thet the server can send data.


something like:

AT+AIPO=1,10000,"14.97.98.47",8080,0

so on 10000 port we listen data from server

解决方案

ACM8068 is a small-size and low-cost quad-band GSM/GPRS modem module. By using the ACM8068, you can deliver world-class performance in M2M, mobile voice/data and public phone applications.
Unparalleled quad-band RF performance and sensitivity of ACM8068 result in expanded GSM network coverage and fewer dropped calls. ACM8068 provides user with higher flexibility and reduced time-to-market when incorporating voice and data communications into variety applications.

ACM8068 is controlled by AT commands, with AT/Telecom command middleware, it enables users to have easy-to-use solution and highly-reliable modem to shorten your design cycle and simplify your efforts.


http://www.amod.com.tw/Product/product_more.asp?vrlSholMe7iBxJO2wrpSmKiigJylp6h1pLSBysm+wLOI[^]

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