我们可以在非静态成员函数中使用静态数据成员吗? [英] can we use the static data member in the non static member function?

问题描述

#include iostream.h // Brackets removed
#include conio.h // Brackets removed

class X
{
   static int x;
   public:
   void fun()
   {
      cout<<x;
   }
};

int main()
{
   X o;
   o.fun();
   getch();
   return 0;
}

推荐答案

是的.静态类成员可用于任何类实例.

您不能做的是从静态方法中引用普通成员，因为该方法没有"this"指针.

Yes you can. The static class member is available to any class instance.

What you cannot do is reference a plain member from a static method, because the method doesn''t have the ''this'' pointer.

是的，请不要忘记初始化您的静态对象(如果您在标头中执行此操作，请不要忘记标头保护符，这样它就不会被多次包含):

Yes, just don''t forget to initialize your static (if you''re doing it in the header, don''t forget header guards so it doesn''t get included more than once):

#ifndef MYCLASS_X
#define MYCLASS_X

class X
{
   static int x;
   public:
   void fun()
   {
      cout<<x;
   }
};
int X::x = 0;

#endif //MYCLASS_X

如果在X的构造函数中初始化x的值，则可以.如果不初始化，我不确定会发生什么，但是我认为您会在这种情况下会产生错误.

You can if you initialize the value of x in the constructor for X. If you don''t, I''m not sure what would happen, but I think you would generate an error in that situation.

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