从另一个基于PHP的DropDownList自动填充DropDownList [英] Auto Populate DropDownList from another DropDownList based in PHP
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问题描述
我试图根据另一个下拉列表选择填充一个下拉列表，但没有得到结果.贝娄是我的代码，请告诉我我哪里错了.
控制器:index.php
Hi,
I am trying to populate a dropdownlist based on another dropdownlist selection and not getting the result. Bellow is my code, Please tell me where I am wrong.
The Controller: index.php
$link = mysqli_connect('localhost', 'root', 'aweklin@topnetconsulting');
if (!$link){
echo 'There was an error connecting to database server: ' . mysqli_error($link);
exit();
}
if (!mysqli_select_db($link, 'practice')){
echo 'There was an error selecting practice database: ' . mysqli_error($link);
exit();
}
$sql = "SELECT cat_id, category FROM category ORDER BY category";
$result = mysqli_query($link, $sql);
if (!$result){
echo 'There was an error fetching categories: ' . mysqli_error($link);
exit();
}
while ($row = mysqli_fetch_array($result)){
$categories[] = array('catid' => $row['cat_id'], 'cat' => $row['category']);
}
if (isset($_REQUEST['catDDL'])){
$catid = $_REQUEST['catDDL'];
$sql = "SELECT subcat_id, subcategory FROM category WHERE cat_id = '$catid' ORDER BY category";
$result = mysqli_query($link, $sql);
if (!$result){
echo 'There was an error fetching subcategories: ' . mysqli_error($link);
exit();
}
while ($row = mysqli_fetch_array($result)){
$subcategories[] = array('catid' => $row['subcat_id'], 'cat' => $row['subcategory']);
}
}
include 'test.html.php';
?>
表格:text.html.php
The Form: text.html.php
<pre lang="PHP"><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
<title>Categories</title>
<script type="text/javascript">
function populateSubCategory(){
window.location = ''index.php'';
}
</script>
</head>
<body>
<form id="catform" action="index.php" method="post">
Category:
<select id="catDDL" name="catDDL" önchange="populateSubCategory();">
<option value="">Select One<option
<?php if(isset($categories)): ?><br mode="hold" /?> <?php foreach($categories as $category): ??>
<option value="<?php echo $category[''catid'']; ?>"?>
<?php echo $category[''cat'']; ??>
</option>
<?php endforeach; ??>
<?php endif; ??>
</select>
<br />
Sub Category:
<select id="subCatDDL" name="subCatDDL">
<option value="">Select sub category</option>
<?php if(isset($subcategories)): ??>
<?php foreach($subcategories as $subcategory): ??>
<option value="<?php echo $subcategory[''catid'']; ?>"?>
<?php echo $subcategory[''cat'']; ??>
</option>
<?php endforeach; ??>
<?php endif; ??>
</select>
</form>
</body>
</html>
推荐答案
link = mysqli_connect(' ' ' 如果(！
link = mysqli_connect('localhost', 'root', 'aweklin@topnetconsulting'); if (!
链接){ echo ' 连接到数据库服务器时出错:' . mysqli_error(
link){ echo 'There was an error connecting to database server: ' . mysqli_error(
链接); 出口(); } 如果(！mysqli_select_db(
link); exit(); } if (!mysqli_select_db(
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