如何使SOAP请求 [英] How to make the SOAP request
本文介绍了如何使SOAP请求的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在做Android的SOAP请求。究竟我想实现的是：
＆LT;肥皂：信封的xmlns：SOAP =http://www.w3.org/2003/05/soap-envelope的xmlns：TEM =HTTP：// tempuri .ORG /＆GT;
＆LT;肥皂：页眉/＆GT;
＆LT;肥皂：身体与GT;
＆LT; TEM：GeneratePin＆GT; ＆LT; TEM：sEmail＆GT; xyz@abc.com< / TEM：sEmail＆GT; ＆LT; TEM：sFlage＆GT;真＆LT; / TEM：sFlage＆GT;
＆LT; / TEM：GeneratePin＆GT;
＆LT; / SOAP：身体与GT;
＆LT; / SOAP：信封＆GT;
但我正在逐渐：
＆LT;五：信封的xmlns：I =http://www.w3.org/2001/XMLSchema-instance的xmlns：D =HTTP：//www.w3 .ORG / 2001 / XML模式的xmlns：C =http://www.w3.org/2003/05/soap-encoding的xmlns：v =后面http://www.w3.org/2003/05/soap -envelope＆GT;
＆LT;五：页眉/＆GT;
＆LT;五：身体与GT;
＆LT; TEM：GeneratePin的xmlns =http://www.tempuri.org/＆GT;
＆LT; TEM：sEmail＆GT; abc@xyz.com< / TEM：sEmail＆GT;
＆LT; TEM：sFlage＆GT;真＆LT; / TEM：sFlage＆GT;
＆LT; / TEM：GeneratePin＆GT;
＆LT; / V：车身＆GT;
＆LT; / V：信封＆GT;
我用下面的code：
静态字符串SOAP_ACTION =http://tempuri.org/GeneratePin;
静态字符串命名空间=http://www.tempuri.org/;
私有静态字符串URL =XYZ; 静态SoapObject请求= NULL;
静态SoapSerializationEnvelope信封;
静态HttpTransportSE androidHttpTransport; //方法名变量定义Web服务哪些函数将调用
公共静态字符串getPin（字符串方法名）{ 尝试{
请求=新SoapObject（命名空间，TEM：GeneratePin）; / *
* PI的PropertyInfo =新的PropertyInfo（）; pi.setName（sEmail）;
* pi.setValue（rishabh@vervesys.local）; request.addProperty（PI）;
*
*的PropertyInfo PI1 =新的PropertyInfo（）; pi1.setName（sFlage）;
* pi1.setValue（真）; request.addProperty（PI1）;
* / request.addProperty（TEM：sEmail，abc@xyz.com）;
request.addProperty（TEM：sFlage，真）; 的System.out.println（要求是：==+请求）;
信封=新SoapSerializationEnvelope（SoapEnvelope.VER12）;
envelope.dotNet = TRUE;
envelope.implicitTypes = TRUE;
envelope.setAddAdornments（假）;
envelope.encodingStyle =UTF-8;
envelope.setOutputSoapObject（请求）;
/ *
* MarshalDouble marshaldDouble =新MarshalDouble（）;
* marshaldDouble.register（信封）;
* / androidHttpTransport =新HttpTransportSE（URL）;
androidHttpTransport.debug = TRUE; androidHttpTransport.call（SOAP_ACTION，信封）;
System.out的
.println（！ONE @＃$％^＆安培;+ androidHttpTransport.requestDump）;
/ *
* androidHttpTransport
* .setXmlVersionTag（＆下; XML版本= \\1.0 \\编码= \\UTF-8 \\＆GT;）;
* /
最后SoapPrimitive响应=（SoapPrimitive）信封
.getResponse（）;
Log.i（web服务输出，response.toString（））;
返回response.toString（）; }赶上（例外五）{
e.printStackTrace（）;
}
返回null;
}
解决方案
它看起来像KSOAP有一个硬codeD的命名空间的SoapEnvelope 值：
<一个href=\"https://github.com/karlmdavis/ksoap2-android/blob/master/ksoap2-base/src/main/java/org/ksoap2/SoapEnvelope.java#L182\" rel=\"nofollow\">https://github.com/karlmdavis/ksoap2-android/blob/master/ksoap2-base/src/main/java/org/ksoap2/SoapEnvelope.java#L182
/ **
*写完整的包膜，包括标题和正文元素到
*给定的XML作家。
* /
公共无效写入（XmlSerializer的作家）抛出IOException
writer.set preFIX（I，XSI）;
writer.set preFIX（D，XSD）;
writer.set preFIX（C，ENC）;
writer.set preFIX（V，ENV）;
writer.startTag（ENV，信封）;
writer.startTag（ENV，页眉）;
writeHeader（作家）;
writer.endTag（ENV，页眉）;
writer.startTag（ENV，身体）;
writeBody（作家）;
writer.endTag（ENV，身体）;
writer.endTag（ENV，信封）;
}
的 SoapSerializationEnvelope 你在这里创造：
信封=新SoapSerializationEnvelope（SoapEnvelope.VER12）;
...是的SoapEnvelope 的子类。所以，去改变，你需要继承 SoapSerializationEnvelope 像这样：
公共类CustomSoapSerializationEnvelope扩展SoapSerializationEnvelope { @覆盖
公共无效写入（XmlSerializer的作家）抛出IOException
writer.set preFIX（I，XSI）;
writer.set preFIX（D，XSD）;
writer.set preFIX（C，ENC）;
writer.set preFIX（肥皂，ENV）; //＆LT; - 改线
writer.startTag（ENV，信封）;
writer.startTag（ENV，页眉）;
writeHeader（作家）;
writer.endTag（ENV，页眉）;
writer.startTag（ENV，身体）;
writeBody（作家）;
writer.endTag（ENV，身体）;
writer.endTag（ENV，信封）;
}
}
然后，替换上述行：
信封=新CustomSoapSerializationEnvelope（SoapEnvelope.VER12）;
I am making a SOAP request in Android. What exactly I want to achieve is:
<soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:tem="http://tempuri.org/">
<soap:Header/>
<soap:Body>
<tem:GeneratePin>
<tem:sEmail>xyz@abc.com</tem:sEmail>
<tem:sFlage>true</tem:sFlage>
</tem:GeneratePin>
</soap:Body>
</soap:Envelope>
but I am getting:
<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema" xmlns:c="http://www.w3.org/2003/05/soap-encoding" xmlns:v="http://www.w3.org/2003/05/soap-envelope">
<v:Header />
<v:Body>
<tem:GeneratePin xmlns="http://www.tempuri.org/">
<tem:sEmail>abc@xyz.com</tem:sEmail>
<tem:sFlage>true</tem:sFlage>
</tem:GeneratePin>
</v:Body>
</v:Envelope>
I am using the following code:
static String SOAP_ACTION = "http://tempuri.org/GeneratePin";
static String namespace = "http://www.tempuri.org/";
private static String url = "xyz";
static SoapObject request = null;
static SoapSerializationEnvelope envelope;
static HttpTransportSE androidHttpTransport;
// MethodName variable is define for which webservice function will call
public static String getPin(String MethodName) {
try {
request = new SoapObject(namespace, "tem:GeneratePin");
/*
* PropertyInfo pi = new PropertyInfo(); pi.setName("sEmail");
* pi.setValue("rishabh@vervesys.local"); request.addProperty(pi);
*
* PropertyInfo pi1 = new PropertyInfo(); pi1.setName("sFlage");
* pi1.setValue("true"); request.addProperty(pi1);
*/
request.addProperty("tem:sEmail", "abc@xyz.com");
request.addProperty("tem:sFlage", "true");
System.out.println("request is : == " + request);
envelope = new SoapSerializationEnvelope(SoapEnvelope.VER12);
envelope.dotNet = true;
envelope.implicitTypes = true;
envelope.setAddAdornments(false);
envelope.encodingStyle = "utf-8";
envelope.setOutputSoapObject(request);
/*
* MarshalDouble marshaldDouble = new MarshalDouble();
* marshaldDouble.register(envelope);
*/
androidHttpTransport = new HttpTransportSE(url);
androidHttpTransport.debug = true;
androidHttpTransport.call(SOAP_ACTION, envelope);
System.out
.println("ONE!@#$%^& " + androidHttpTransport.requestDump);
/*
* androidHttpTransport
* .setXmlVersionTag("<?xml version=\"1.0\" encoding=\"UTF-8\"?>");
*/
final SoapPrimitive response = (SoapPrimitive) envelope
.getResponse();
Log.i("Webservice Output", response.toString());
return response.toString();
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
解决方案
It looks like KSoap has a hardcoded value for the namespace in SoapEnvelope:
/**
* Writes the complete envelope including header and body elements to the
* given XML writer.
*/
public void write(XmlSerializer writer) throws IOException {
writer.setPrefix("i", xsi);
writer.setPrefix("d", xsd);
writer.setPrefix("c", enc);
writer.setPrefix("v", env);
writer.startTag(env, "Envelope");
writer.startTag(env, "Header");
writeHeader(writer);
writer.endTag(env, "Header");
writer.startTag(env, "Body");
writeBody(writer);
writer.endTag(env, "Body");
writer.endTag(env, "Envelope");
}
The SoapSerializationEnvelope you're creating here:
envelope = new SoapSerializationEnvelope(SoapEnvelope.VER12);
…is a subclass of SoapEnvelope. So, to change the behaviour, you need to subclass SoapSerializationEnvelope like so:
public class CustomSoapSerializationEnvelope extends SoapSerializationEnvelope {
@Override
public void write(XmlSerializer writer) throws IOException {
writer.setPrefix("i", xsi);
writer.setPrefix("d", xsd);
writer.setPrefix("c", enc);
writer.setPrefix("soap", env); // <-- changed line
writer.startTag(env, "Envelope");
writer.startTag(env, "Header");
writeHeader(writer);
writer.endTag(env, "Header");
writer.startTag(env, "Body");
writeBody(writer);
writer.endTag(env, "Body");
writer.endTag(env, "Envelope");
}
}
Then, replace the above line with:
envelope = new CustomSoapSerializationEnvelope(SoapEnvelope.VER12);
这篇关于如何使SOAP请求的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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