使用JQuery调用函数后的代码未完成，但是页面正在刷新 [英] code behond function calling using JQuery but page is refreshing

问题描述

大家好，
我正在尝试使用jquery调用函数背后的代码，但是在调用函数时页面被引用，任何帮助将不胜感激

hi all,
I am trying to call a code behind function using jquery but page is refershing when function is called, any help will be appreciated

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js" type="text/javascript"></script>
		



<script type = "text/javascript">
    function ShowCurrentTime() {
        $.ajax({
            type: "POST",
            url: "default2.aspx/ServerSideMethod",
            data: ''{}'',
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            async: true,
            cache: false,
            success: OnSuccess,
            failure: function (response) {
                alert(response.d);
            }
        });
    }
    function OnSuccess(response) {
        alert(response.d);
    }
</script>

--------------------------------

.cs函数

--------------------------------

.cs function

[System.Web.Services.WebMethod]
   public static string ServerSideMethod()
   {
       return "Hello, this is string message";
   }

推荐答案

.ajax({ 输入:"POST"， 网址:"default2.aspx/ServerSideMethod"， 数据: ''{}''， contentType:"application/json; charset = utf-8"， dataType:"json"， 异步:是的， 快取:false， 成功:OnSuccess， 失败:功能(响应){ 警报(response.d); } }); } 函数OnSuccess(response){ 警报(response.d); } </script>

.ajax({ type: "POST", url: "default2.aspx/ServerSideMethod", data: ''{}'', contentType: "application/json; charset=utf-8", dataType: "json", async: true, cache: false, success: OnSuccess, failure: function (response) { alert(response.d); } }); } function OnSuccess(response) { alert(response.d); } </script>

--------------------------------

.cs函数

--------------------------------

.cs function

[System.Web.Services.WebMethod]
   public static string ServerSideMethod()
   {
       return "Hello, this is string message";
   }

Onclientclick必须返回false以避免回发.

Onclientclick must return false to avoid a postback.

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js" type="text/javascript"></script>
<script type = "text/javascript">
    function ShowCurrentTime() {

这篇关于使用JQuery调用函数后的代码未完成，但是页面正在刷新的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！