四舍五入浮动值 [英] Rounding off floating values

问题描述

我如何将浮点数四舍五入为int(非浮点值)

例如22.69至23
19.7至20
16.5至17

17.4至17
17.2至17

我试图将float或double转换为int，但没有得到想要的结果

坚强，我已经尝试过

双数= 19.7;

int number2 =(int)(数字)

number2 = 19;
这不是我想要达到的目标

在此先感谢

您的马丁

Hi there, how can i round off a floating number to an int (non floating value)

E.g 22.69 To 23
19.7 To 20
16.5 To 17

17.4 To 17
17.2 To 17

I have tried to cast float or double to int but i don''t get the desired results

Foristance,i have tried

double number = 19.7;

int number2=(int)(number)

number2=19;
This is not what i want to achieve

Thanks in advance

Yours Martin

推荐答案

尝试使用数学计算

您需要使用数学.舍入(值， MidpointRoundingMode ) [ ^ ].您需要使用AwayFromZero选项.

在弄乱代码之前，请确保已阅读整个页面.

You need to use Math.Round(value, MidpointRoundingMode)[^]. You need to use the AwayFromZero option.

Make sure you read the entire page before you go screwing up your code.

System.Math.Round(myNumber);

我认为是正确的.

System.Math.Round(myNumber);

That''s right I think.

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