麻烦终止字符串 [英] Trouble Terminate strings
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问题描述
有人可以帮忙解释一下这是做什么的吗
字符缓冲区[40];
buffer [0] =``h'';
buffer [1] =``i'';
buffer [2] =''\ 0'';
printf(%s \ r \ n字符串结尾",buffer);
此代码打印
然后是40个空格,然后是字符串的结尾
我想用CR-LF来打个招呼
Can someone help explain what this is doning
Char buffer[40];
buffer[0] = ''h'';
buffer[1] = ''i'';
buffer[2] = ''\0'';
printf("%s\r\n end of string",buffer);
this code prints
hi then 40 spaces then end of string
I whant it to just print hi with a CR-LF
推荐答案
好的,我会尝试的.
首先,它不会先打印"hi",然后再打印40个空格,然后再打印"string of end". -尽管看起来确实很强大,但是看起来确实很相似. ;)
它打印"hi",然后将光标返回到该行的开头,然后前进到下一行的开头,最后它显示字符串的结尾"
不相信我吗?只需从printf语句中删除\ n,您将看到"hi"不可见-这是因为"string of end"已打印在其顶部.
要打印"hi",然后换行,然后字符串结尾",请使用以下命令:
Sure, I''ll try.
Firstly, it does not print "hi" then 40 spaces then "end of string". - Although it does look mighty similar to what would be seen if it did. ;)
It prints "hi", then it returns the cursor to the start of that line then it advances to the start of the next line, finally it prints " end of the string"
Don''t believe me? Just remove the \n from your printf statement and you''ll see that "hi" is not visible - that''s because " end of the string" has been printed over the top of it.
To print "hi", then a new line, then "end of the string" use the following:
printf("%s\nend of the string", buffer);
buffer [2] =''\ r''
buffer [3] =''\ n''
buffer[2] = ''\r''
buffer[3] = ''\n''
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