安卓：检查网络和实时互联网连接 [英] Android: Check network and real internet connectivity
问题描述
下面是一块的Android code的工作正常，检查网络连接或没有。
Below is the piece of Android code which works fine to check if network is connected or not.
public static boolean isNetworkAvailable(Context context)
{
ConnectivityManager mConnectivityManager = (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);
return (mConnectivityManager != null && mConnectivityManager.getActiveNetworkInfo().isConnectedOrConnecting()) ? true : false;
}
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
但有一个活跃的网络接口不能保证一个特定的网络服务。
But having an active network interface doesn't guarantee that a particular networked service is available.
很多时候发生，我们都连接到网络，但还没有到达共同的互联网网络服务，例如，谷歌
A lot of time happens that we are connected to network but still not reachable to common internet network services, e.g. Google
常见的场景：
- 连接到Wi-Fi无线Android设备，这原来是一个私人
网络。所以isNetworkAvailable将返回的网络连接，但也
不连接到任何其他服务 - 有些时候，手机信号显示它连接到服务提供商的数据计划。所以网络连接是真的，但仍无法访问谷歌/雅虎。
的一种方法是检查是否isNetworkAvailable函数返回TRUE，然后按照code运行
HttpGet request = new HttpGet(url));
HttpParams httpParameters = new BasicHttpParams();
int timeoutConnection = 60000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
int timeoutSocket = 60000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
request.addHeader("Content-Type", "application/json");
HttpResponse response = httpClient.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null)
{
result = EntityUtils.toString(entity);
}
}
catch (SocketException e)
{
return "Socket Exceptiopn:" + e.toString();
}
catch (Exception e)
{
return "General Execption:" + e.toString();
}
但我认为这并不是因为它可能会消耗大量时间的好方法。
But I think this is not an good way because it may consume lot of time
那么，有没有替代的高效率（在时间上采取的，速度）的方式确保我们连接到网络，以及可达最常用的互联网服务？
推荐答案
检查该code ......它为我工作：）
check this code... it worked for me :)
public static void isNetworkAvailable(final Handler handler, final int timeout) {
// ask fo message '0' (not connected) or '1' (connected) on 'handler'
// the answer must be send before before within the 'timeout' (in milliseconds)
new Thread() {
private boolean responded = false;
@Override
public void run() {
// set 'responded' to TRUE if is able to connect with google mobile (responds fast)
new Thread() {
@Override
public void run() {
HttpGet requestForTest = new HttpGet("http://m.google.com");
try {
new DefaultHttpClient().execute(requestForTest); // can last...
responded = true;
} catch (Exception e) {}
}
}.start();
try {
int waited = 0;
while(!responded && (waited < timeout)) {
sleep(100);
if(!responded ) {
waited += 100;
}
}
}
catch(InterruptedException e) {} // do nothing
finally {
if (!responded) { handler.sendEmptyMessage(0); }
else { handler.sendEmptyMessage(1); }
}
}
}.start();
}
然后，我定义的处理程序：
Then, I define the handler:
Handler h = new Handler() {
@Override
public void handleMessage(Message msg) {
if (msg.what != 1) { // code if not connected
} else { // code if connected
}
}
};
和启动测试：
isNetworkAvailable(h,2000); // get the answser within 2000 ms
从Gilbou http://stackoverflow.com/a/5803489/2603719
code
我希望我可以帮你。
I hope i can Help you
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