打开一个具有动态生成的文件名并带有日期的文件 [英] Open a file that has a dynamically generated file name with date

问题描述

全部，
如何打开动态生成的文件?
例如，这里是代码:

All,
How would I open a dynamically generated file?
For instance here is code:

StreamReader reader = File.OpenText(@"C:\Users\Iman\Downloads\tandem-win32-10-12-01-1\tandem-win32-10-12-01-1\bin\output.xml");

但是output.xml每次都是使用上一个具有日期和时间的先前进程创建的，例如:output.2011_07_06_23_34_53.t

but the output.xml is created every time with a previous process with date and time like: output.2011_07_06_23_34_53.t

推荐答案

我可能会使用类似

I would probably use something like

DirectoryInfo dir_info = new DirectoryInfo(my_file_path);
FileSystemInfo[] my_files = dir_info.GetFileSystemInfo("output.*");

将文件信息放入数组中，然后使用Array.Sort()查找最新文件并从该位置开始.

to put the file information in an array, then use Array.Sort() to find the newest file and go from there.

对于时间的字符串表示，最好使用特殊格式称为可排序" .

Prefer using special format for string representation of time called "sortable".

string time = System.DateTime.Now.ToString("s").Replace(':', '-');
// it will be formatted like 2011-06-15T13-45-30
// ':' should be removed to comply with
// the requirements for file system names

// just for example:
string fileName = string.Format("output.{0}.xml", time);

格式"s"是专门为此类设计的.您是否按字母数字顺序对文件进行排序，它将与按时间顺序相同.

参见:
http://msdn.microsoft.com/en-us/library/1k1skd40.aspx [ ^ ]，
http://msdn.microsoft.com/en-us/library/az4se3k1.aspx [ ^ ].

—SA

The format "s" is specially designed for such things. Is you sort your files by alphanumeric order, it will be the same as the order by time.

See:
http://msdn.microsoft.com/en-us/library/1k1skd40.aspx[^],
http://msdn.microsoft.com/en-us/library/az4se3k1.aspx[^].

—SA

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