当用户选择gridview行时，如何使用AJAX打开弹出窗口? [英] How to use AJAX to open a popup as user selects a gridview row?

问题描述

我在网页上有网格视图.

现在，我想在用户选择一行网格后打开一个弹出窗口.

网格将包含部分信息，弹出窗口将显示完整信息.

我没有找到解决方法，请在这方面帮助我.

谢谢！

Hi,

I have a grid view on a webpage.

Now i want to open a popup window once a user selects a row of a grid.

The grid would contain partial info and popup window would display complete information.

I am not finding a way to do this, please help me in this regard.

Thanks!

推荐答案

jqModal是一个用于显示弹出窗口的插件.检查以下链接以了解如何将其与gridview一起使用.

参考: http://mosesofegypt.net/post/Popup- Master-Detail-using-GridViewDetailsView-and-JQuery-with-jqModal.aspx [

jqModal is a plugin to show popups. Check following link to see how to use it with gridview.

Ref:http://mosesofegypt.net/post/Popup-Master-Detail-using-GridViewDetailsView-and-JQuery-with-jqModal.aspx[^]

Patel已经为您提供了一个不错的链接.以下是更有用的链接.
使用ModalPopup Extender和GridView显示主细节数据
具有GridView，DetailsView和jQuery的ThickBox的主-细节

Patel already provided you a nice link. Following are more useful links.
Display Master-Detail Data with the ModalPopup Extender and GridView
Master-Detail with the GridView, DetailsView and jQuery''s ThickBox

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