如何随机生成不同长度的字符串. [英] How to randomly generate different variable length string .the srting be unique.?

问题描述

我创建了一个用于自动随机生成字符串的函数
我在下面给出的功能:

Hi i created one function for automatic random generation of string
The function i geiven below:

public static string createRandomString(int Length)
       {
           string _allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ";
           Random randNum = new Random();
           char[] chars = new char[Length];
           int allowedCharCount = _allowedChars.Length;

           for (int i = 0; i < Length; i++)
           {
               chars[i] = _allowedChars[(int)((_allowedChars.Length) * randNum.NextDouble())];
           }

           return new string(chars);
       }

在长度上，我正在传递varchar长度.即varchar(50)表示我正在传递50长度.它随机生成字符串需要50​​个全长



它最多生成50个字符的字符串

但是我想要可变长度的字符.也就是说，如果我给定长度50，它想在50内产生类似不同长度的字符串..不超过50

那是
例如；

addncvu
axccdfgghh
wdedglikdfdf
adsd
asdfeddfgdfgdfsggggfgfd
advefcvv
adfsadfafccffgbbb


像这样我想改变字符串的长度..如何生成它..如何对我已经编写的函数进行mdodify ..
有人知道告诉我.........

here in length i am passing the varchar length..ie varchar(50) mean i am passing lenght 50.it randomly generate string takes 50 whole length



it generate string upto 50 characters

but i want variable lenght characters.that is if i gave length 50 it want to produce string like different length within 50 ..not exceeds 50

that is
eg;

addncvu
axccdfgghh
wdedglikdfdf
adsd
asdfeddfgdfgdfsggggfgfd
advefcvv
adfsadfafccffgbbb


like this i want to vary the length of string..how to generate it..how to mdodify the function i have written already..
anybody know tell me.........

推荐答案

要随机化字符串的长度，请创建一个1到50的随机数.为此，您可以使用随机 [

To randomize the length of the string, you create a random number from 1 to 50. And to do that, you use Random[^] class. Please see example below.

System.Random RandNum = new System.Random();
int MyRandomNumber = RandNum.Next(1, 51);

这篇文章将为您提供更好的方法.为了生成随机长度的字符串，长度" i/p参数应由"Random"类实例提供，其最大值为50.

希望对您有所帮助！

This article will give you a better approach. Further to generate random length string, the "length" i/p parameter should be provided by a "Random" class instance with max value as say 50.

Hope this helps!

您可以像这样使用
这将生成一个随机长度小于您在Length变量中指定的长度的字符串.

You can use like this
This will generate a string which has a random length less than you have given in Length variable.

public static string createRandomString(int Length)
       {
           string _allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ";
           Random randNum = new Random();
           char[] chars = new char[Length];
           int allowedCharCount = _allowedChars.Length;
           for (int i = 0; i < randNum.NextDouble(1,Length); i++)
           {
               chars[i] = _allowedChars[(int)((_allowedChars.Length) * randNum.NextDouble())];
           }
           return new string(chars);
       }

您还可以使用此代码生成随机字符串

You can Also Use this code to generate Random String

String RndString;
Int Zero, Nine, A, Z, Count, RandNum;
Random randNum;
Random oRandom = New Random(System.DateTime.Now.Millisecond);
Zero = Asc("0");
Z = Asc("Z");
While (Count < randNum.NextDouble(1,Length))
{
    RandNum = oRandom.Next(Zero, Z);
    RndString = (char)RandNum;
    Count++;
}

谢谢.

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