写入用户输入的文件名 [英] Writing to a file name input by user

问题描述

我创建了一个Windows窗体应用程序，其中一部分包括从文本框中获取名称并将其附加到目录中，以便写入该目录中的文件.

最高级别始终是C:\ Programs \ PROGRAMS \

这是我现在要为构造函数提供的内容(这不是我真正想要的方式，只是想提供一些我正在查看的内容):

createFile::createFile(string name)
{
	string path = "C:\\Programs\\PROGRAMS\\" + name + "\\" + name + ".txt";	
}

例如，我想写入的文件可能是:
C:\ Programs \ PROGRAMS \ ATP-8878B \ ATP-8878B.txt
我希望能够使用
ofstream outFile;
outFile.open(path);

我得到的错误是:试图从受保护的内存中读取或写入.
在第一个strcat()调用中.

可以将参数(const char *名称)更改为其他类型，因为无论如何它都需要从String ^进行转换，如果您认为这样做会有所帮助的话.根据我的发现，路径最终必须是const char *才能调用outFile.open(path);

有什么更好的方法可以做到这一点吗?
在此先感谢您的帮助.


修改后的原始代码.
在将构造函数中的代码更改为现在我最高职位中的代码之后，解决方案很简单:

ofstream outFile;
outFile.open(path.c_str());

您其他代码无效的原因是您拥有:

createFile::createFile(const char* name)
{
    char* path = "C:\\Programs\\PROGRAMS\\";

    path = strcat(path, name);
    path = strcat(path, (const char*)''\\'');
    path = strcat(path, name);
    path = strcat(path, (const char*)''.txt'');
}

什么时候应该有这样的事情:

createFile::createFile(const char*name)
{
    char path[] = "C:\\Programs\\PROGRAMS\\";

    strcat(path, name);
    strcat(path, (const char*)"\\");
    strcat(path, name);
    strcat(path, (const char*)".txt");
}

I have created a Windows form app and part of it includes getting a name out of a text box and appending it to a directory in order to write to a file in that directory.

The top level will always be C:\Programs\PROGRAMS\

Here is what I have right now for my constructor (This is not how I actually want to do it, just wanted to provide some idea of what I''m looking at):

createFile::createFile(string name)
{
	string path = "C:\\Programs\\PROGRAMS\\" + name + "\\" + name + ".txt";	
}

So for example a file I would like to write to could be:
C:\Programs\PROGRAMS\ATP-8878B\ATP-8878B.txt
and I would like to be able to use
ofstream outFile;
outFile.open(path);

The error I get is: Attempting to read or write from protected memory.
at the first strcat() call.

The parameter (const char* name) can be changed to another type, as it needs to be converted from a String^ anyway, if you think that could be helpful. From what I''ve found path needs to end up being a const char* in order to call outFile.open(path);

Any ideas on a better way I can do this?
Thanks in advance for any help.

EDIT:
Modified original code.

解决方案

Sorry to waste anyone''s time who read this... apparently I just wasn''t thinking clearly.

After changing the code in the constructor to what it now in my top post, the solution was simply:

ofstream outFile;
outFile.open(path.c_str());

The reason your other code wasn''t working was that you had:

createFile::createFile(const char* name)
{
    char* path = "C:\\Programs\\PROGRAMS\\";

    path = strcat(path, name);
    path = strcat(path, (const char*)''\\'');
    path = strcat(path, name);
    path = strcat(path, (const char*)''.txt'');
}

when you should''ve probably had something like this:

createFile::createFile(const char*name)
{
    char path[] = "C:\\Programs\\PROGRAMS\\";

    strcat(path, name);
    strcat(path, (const char*)"\\");
    strcat(path, name);
    strcat(path, (const char*)".txt");
}

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