我该如何使用循环呢? [英] how can i do this using loops ?

问题描述

我想做这样的形状:

* * * * *
* * * *
* * *
* *
*

代码:

public void displayPyramid(int x, int y)
{
  row = x;
  col = y;
  int r =0;
  int c =0;
  
  while(r<row)>
   {
      while(c<col)>
       { 
        System.out.println("* ");
        c++;
       }
       System.out.println();
       r++;
   }
}

解决方案

算法步骤:
1.从5步到1步-1开始循环
2.根据当前循环号显示星星
3.循环减小1
时，请换行
完毕！尝试！

查看图表并计算开头的空格数以及每行上的星星总数.这样应该可以为您提供关于每行所需的循环计数器的合理线索.

for (int i = 5; i > 0; i--)
{
    int y = 5;
    y = y - i;
    for (int e = y; e > 0; e--)
    {
        Console.Write(" ");
    }
    for (int j = i; j > 0; j--)
    {
        Console.Write("* ");
    }
    Console.Write("\n");
}

Eshaq

i want to do this shape :

* * * * *
* * * *
* * *
* *
*

code :

public void displayPyramid(int x, int y)
{
  row = x;
  col = y;
  int r =0;
  int c =0;
  
  while(r<row)>
   {
      while(c<col)>
       { 
        System.out.println("* ");
        c++;
       }
       System.out.println();
       r++;
   }
}

解决方案

Algo Steps:
1. Start loop from 5 to 1 step -1
2. Show the stars as per the current loop number
3. Put a line break when the loop is reduced by 1

Done! Try!

Look at your diagram and count the number of spaces at the beginning, and total number of stars on each line. That should give you a reasonable clue as to the loop counters you need for each row.

You can try this, may it help you

for (int i = 5; i > 0; i--)
{
    int y = 5;
    y = y - i;
    for (int e = y; e > 0; e--)
    {
        Console.Write(" ");
    }
    for (int j = i; j > 0; j--)
    {
        Console.Write("* ");
    }
    Console.Write("\n");
}

Eshaq

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