在GridView的模型弹出窗口中编辑项目模板 [英] Edit Item template in model popup in GridView

问题描述

< asp:CommandField ShowEditButton ="True"/>



当单击此命令的网格视图的字段编辑按钮时，应在AJAX的ModelPop中显示编辑项目模板"..

<asp:CommandField ShowEditButton="True"/>



when click this commandField edit button of gird view then EDIT ITEM Template should be displayed in ModelPop up of AJAX..

推荐答案

Hello Vineet，

首先，您需要将命令编辑"按钮转换为Templete字段.

然后在gridview的templete中创建一个模型弹出面板，并进行相应的绑定.

将模型弹出窗口的目标设置为编辑按钮.

如果可以帮助您，请尝试此操作.

谢谢

Pankaj

Hello Vineet,

First you need to convert Command Edit button to Templete field.

Then make a model pop panel inside edit templete of gridview and bind accordingly.

Set target of model popup to edit button.

Try this, if it could help you.

Thanks

Pankaj

查看此链接

http://mattberseth.com/blog/2007/07/modalpopupextender_example_for.html [ ^ ]

http://mattberseth2.com/demo/Default.aspx?Name=Master-Detail+with+the+GridView%2c+DetailsView+and+ModalPopup+Controls&Filter=All# [

see this links

http://mattberseth.com/blog/2007/07/modalpopupextender_example_for.html[^]

http://mattberseth2.com/demo/Default.aspx?Name=Master-Detail+with+the+GridView%2c+DetailsView+and+ModalPopup+Controls&Filter=All#[^]

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