显示未绑定数据的datagrid设计 [英] show design of datagrid without binding data to it
问题描述
我正在使用C#,asp.net,服务器2005和Visual Studio 2005
我的gridview设计看起来像这样:
FIRST_COLUMN | SECOND_COLUMN | THIRD_COLUMN | FOURTH_COLUMN | FIFTH_COLUMN |
------------ ------------- ------------ ------------- ------------
TEXTBOX1 |下拉列表| TEXTBOX2 | TEXTBOX3 | TEXTBOX4 |
当发生StudyIDTextBox_TextChanged(object sender,EventArgs e)事件时,我必须向用户显示此datagridview(设计)而不绑定数据..
请帮我..
问候
karan
I''m using C#,asp.net,server 2005 and visual studio 2005
my gridview design looks like this:
FIRST_COLUMN| SECOND_COLUMN| THIRD_COLUMN| FOURTH_COLUMN| FIFTH_COLUMN|
------------ ------------- ------------ ------------- ------------
TEXTBOX1 | DROPDOWNLIST | TEXTBOX2 | TEXTBOX3 | TEXTBOX4|
i have to display this datagridview (design) to the user without binding data to it when the StudyIDTextBox_TextChanged(object sender, EventArgs e) event occurs..
plz help me..
regards
karan
推荐答案
是的,您可以执行此操作.但我建议使用列模板.
如何在网格视图中动态创建模板列 [
yes you can do this. But I suggest to use Column Templates.
How to create template columns dynamically in a grid view[^]
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