使用查询在SQL中选择同一组的离散总和. [英] select distict sum of same group in SQL using query.

问题描述

朋友，我有一个表，该表具有colum grp和标记，我想从该表中获得标记的总和，但条件是，如果grp相同，则它计数单行，请看表..

表tbgrp

grp标记
1 5
2 4
2 4
3 5
3 5
3 5

我使用查询从tbgrp中选择总和(标记).但显示结果28，实际计数为14，因为5在1组中，4在2组中，5在3组中，所以5 + 4 + 5 = 14但结果为28.

请帮助我，我非常困惑如何获取它.

感谢advace

Parveen Rathi

hi friend i have a table having colume grp and marks i want to get sum of marks from table but the condition is that if the grp is same then it count single rows let see the table..

Table tbgrp

grp marks
1 5
2 4
2 4
3 5
3 5
3 5

i using the query select sum(marks) from tbgrp. but it shows the result 28, in real count is 14 because 5 is in 1 group and 4 is in 2 group and 5 is in 3 group so 5+4+5=14 but the result is 28.

plz help me i am very confuse how to get it.

Thanks in advace

Parveen Rathi

推荐答案

Parveen Rathi

使用此查询

Hi Parveen Rathi

Use this query

SELECT Sum(marks) FROM (SELECT  grp,marks,ROW_NUMBER() OVER
    (PARTITION BY grp ORDER BY grp) AS RowNumber
FROM  Table2   ) as  RankedTable  WHERE RowNumber=1

*使用表名代替Table2

如果组中的标记始终相同，则只需使用Avg聚合或使用上述查询.

* Use your table name in the place of Table2

If the marks in the group always same then simply use an Avg aggregate or else use the above query.

with distinctTable as
(
select distinct * from tbgrp
)
select sum(marks) from distinctTable

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