如何用方法包装一些代码? [英] How to wrap some code with a method?

问题描述

如何用方法包装一些代码?

例如我有以下代码:

Hi,

How can wrap some code with a method?

for example I have this code:

if(x=y)
{
  agent.gotox();
}

我想把它放在一个方法中它不在main中，而在其他.cpp文件中.

谢谢

and I want to put this in a method. It''s not in main and its in other .cpp file.

Thanks

推荐答案

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谢谢您的理解.

—SA

Please kindly consider to stop asking any questions here at CodeProject until you learn the very basics of programming using some elementary book and do most simple exercises on all topic of, say, C++. It should give you enough confidence; and you also will be able to collect some more sensible questions.

When you get this experience, welcome back. This would only make all kind of help from CodeProject members much more effective. Right now, it''s too much of time loss.

Thank you for your understanding.

—SA

以这种方式执行:

Do it in this way:

void my_function(int y,int& x)
{
  if(x=y)
  {
    agent.gotox();
  }
}

但请记住:
if(x=y)就像x=y; if(0!=x) //...
问候.

but remember:
if(x=y) is like x=y; if(0!=x) //...
Regards.

什么类的方法? agent 对象与此类的关系如何?
如果agent是该类的数据成员，则可以使用类似于以下内容的内容:

Method of what class? And how is the agent object related to such class?
If the agent is a data member of the class then you may use something similar to:

//MyClass header file
class MyClass
{
//...
Agent agent;
public:
  void checkAndGo(int x, int y);
//...

// MyClass source file
void MyClass::checkAndGo(int x, int y)
{
  if (x==y)
    agent.goto(x);
}

另一方面，如果agent不是该类的成员，则您必须更改该方法的签名，例如:

on the other hand, if agent isn''t member of the class then you''ve to change the method''s signature, for instance:

void checkAndGo(int x, int y, Agent & agent);

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