链接列表我有小问题 [英] link list little problem that i have

问题描述

// reverse.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include<iostream>
using namespace std;

class node
{
	friend class linklist;
	int data;
	
	node *next;
};

class linklist
{
public:

	linklist() ;
	void insert() ;
	void reverse() ;
	void show() ;

private:
	
	node *first ;
	node *help ;
	node *p;
	node *last;
};

linklist::linklist()
{
	first = help = NULL ;
}

void linklist::insert()
{
	node *p = new node();
	p-> data = NULL ;


	int n ;
	cout << "plz enter the numbers of numbers :" << endl ;
	cin >> n ;
	
	cout << "plz enter the numbers : " << endl ;
	  for(int i = 0 ; i < n ; i++)
		{
			cin >> p -> data ;
		}
		if(first == NULL)
		{
			first = p;
		}
		else
		{
			p -> next = first -> next  ;
			first -> next = p ;
		}

	
}
void linklist::reverse()
{
	node *newlist = NULL ;
	node *current = first ;
	while(current )
		{
			node *next = current ->next;
			current ->next = newlist;
			newlist = current ;
			current = next ;
		}
	

}

void linklist::show()
{
  int r = 2;
  
  cout << "number      "  ;
  node *curPtr = first;
  
  while( curPtr ) {
   
     cout << curPtr -> data << "     ";
   }
		 curPtr = curPtr -> next;
		 r ++;
  
}
int main()
{
	
	linklist m;
	m.insert();
	m.reverse();
	m.show();
	
	return 0;
}

</iostream>

如果我想让我的程序在反向后写所有数字，该怎么办?
它没有做

what should i do if i want my program write all the numbers after reverse ?
it doesnt do

推荐答案

它问数字然后停止工作
看起来这就是您编写的代码.

此处:

it ask the numbers then stop working
Looks like that is the code what you have written.

here:

m.insert();
return 0;

您预计接下来会发生什么?看起来只是按照书面要求执行.

What do you expect to happen next? Looks like it''s just doing as per written.

您还只插入了一个节点.您需要为每个条目创建一个新节点.检查您的for循环范围.

You are also inserting only one node. You need to create a new node for each entry. Check the scope of your for-loop.

for(int i = 0 ; i < n ; i++)
{
    node *p = new node();
    cin >> p -> data ;

    if(first == NULL) // Change to equality test instead of assignment
    {
    }
    else
    {
    }
}

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