如何创建具有可变数量的参数的函数！ [英] How to create a function with variable number of arguments !?

问题描述

我想知道如何创建具有可变数量参数的函数！?
printf()这样做！

I am wondering how to create a function with variable number of arguments !?
printf() do that!

推荐答案

请参见此，例如: http://www.go4expert.com/forums/showthread.php?t=17592 [

See this, for example: http://publications.gbdirect.co.uk/c_book/chapter9/stdarg.html[^].

This is related to the order of parameters on stack. To use variable number of arguments, you need to use C calling conventions. This is pretty good explanation and code sample (referring to your printf, by the way): http://www.go4expert.com/forums/showthread.php?t=17592[^].

—SA

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