Asp.net中的Ajax AsynchFileUpload [英] Ajax AsynchFileUpload in Asp.net
问题描述
我在asp.net页面中使用了AsychFileUpload,
使用以下代码上传
I used AsychFileUpload in my asp.net page,
Used the following code to upload
protected void FupFoto_UploadedComplete(object sender, AjaxControlToolkit.AsyncFileUploadEventArgs e)
{
System.Threading.Thread.Sleep(5000);
if (FupFoto.HasFile)
{
string strPath = MapPath("~/EmpImages/") + Path.GetFileName(e.filename);
FupFoto.SaveAs(strPath);
ImgFoto.ImageUrl = strPath;
}
}
执行FupFoto.SaveAs(strPath)
时出现错误,但是文件正在上传到指定的文件夹,但是ImgFoto
没有随文件一起加载
错误是
"There is no source code available for the current location"
我什么也没说.
请帮助我
When executing FupFoto.SaveAs(strPath)
, I am getting an error, But the file is uploading to the specified folder, But the ImgFoto
is not loading with the file
The Error is
"There is no source code available for the current location"
I can''t get anything detailed.
Please help me
推荐答案
尝试一下.
Try this.
ImgFoto.ImageUrl = "~/EmpImages/" + Path.GetFileName(e.filename);
您好
此错误
Hi
This error
The Error is
"There is no source code available for the current location"
是因为您没有脚本管理器.
例如...
aspx内容..
is due to you are not having a script manager.
As an example...
the aspx content..
<asp:Content ID="BodyContent" runat="server" ContentPlaceHolderID="MainContent">
<asp:ToolkitScriptManager ID="ToolkitScriptManager1" runat="server">
</asp:ToolkitScriptManager>
<script type="text/javascript" language="javascript">
function Test(sender,e) {
alert("EmpImages/" + e.get_fileName());
document.getElementById('<%=ImgFoto.ClientID %>').src = "EmpImages/" + e.get_fileName();
}
</script>
<asp:AsyncFileUpload ID="FupFoto" runat="server" OnClientUploadComplete="Test" ClientIDMode="AutoID" OnUploadedComplete="FupFoto_UploadedComplete"/>
<asp:Image ID="ImgFoto" runat="server" ImageUrl="" />
</asp:Content>
在上传完成事件中...
in the upload complete event...
protected void FupFoto_UploadedComplete(object sender, AjaxControlToolkit.AsyncFileUploadEventArgs e)
{
if (FupFoto.HasFile)
{
string strPath = MapPath("~/EmpImages/") + Path.GetFileName(e.filename);
FupFoto.SaveAs(strPath);
}
}
在此示例中应该可以正常工作
it should be working in this example
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