我如何才能以正确的方式编写此程序? [英] HOW i can write this program in a correct way?

问题描述

#include "stdafx.h"
#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;
int jomleTokalame(string *a){
    string s = "";
int count = s.length();
string::iterator i;
int Count = 0;
for (i = s.begin(); i != s.end(); i++)
{
    if(*i != ' ' && *i != '.')
    {
        Count++;
    }
}
cout<<Count<<endl;
}
int main()
{
    string a;
    string s="salam";
    int g;
    cout<<jomleTokalame()<<endl;
}

推荐答案

哇，该代码甚至无法编译. c是一个int变量.因此，您无法像在该代码中那样像指针/数组一样访问它.那只是代码中最明显的错误，我敢肯定，还有其他问题.

您能否确切说明您要在这里做什么?


~~~~~~~~

如果只需要字符串的长度，则只需一行代码即可:

Wow, that code will not even compile. c is an int variable. So you cannot access it like a pointer/array as you have in that code. That''s just the most glaring error in the code, I am sure there are other problems too.

Can you restate exactly what it is you are trying to do here?


~~~~~~~~

If you just want the length of your string, it''s just one line of code to do that:

string s = "test";
int count = s.length();

~~~~~~~~~~

根据您最新的要求(不包括空格和点)，可以执行以下操作:

~~~~~~~~~~

Based on your updated requirements not to include space and dot, here''s what you can do:

string s = "This is a test.";
int count = s.length();
string::iterator it;
int filteredCount = 0;
for (it = s.begin(); it != s.end(); it++)
{
    if(*it != ' ' && *it != '.')
    {
        filteredCount++;
    }
}

Nish的回答非常好.
或者，您可以使用标准的 std :: count_if [

Nish''s answer is excellent.
Alternatively you can use the standard std::count_if[^] algorithm.
Here is a quick example for you:

#include <iostream>
#include <string>
#include <algorithm>

// We will use this filter pradicate with std::count_if
bool filter(char arg)
{
    // Accept all chars except spaces and dots
    return arg != ' ' && arg != '.';
}

int main()
{
    std::string str("Test test. Test test.");
    // Count the symbols in the string using filter
    std::cout << "Count: " << std::count_if(str.begin(), str.end(), filter);
    return 0;
}

您会看到使用count_if算法可以简化很多事情. ;)

You see that using the count_if algorithm could simplify things a lot. ;)

在编辑您发布的代码时，我发现缺少一个右括号(花括号).那是你的问题吗?您收到任何编译错误了吗?

问候.

While editing the code you had posted I found that there was a missing closing brace (curly parenthesis). Was that your problem? Did you receive any compilation errors?

Regards.

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