说的setContentView找不到源 [英] setContentView says source not found

问题描述

我想有一些文字在它的自定义GLSurfaceView，显示在一场比赛的比分。我已经做了基础某人的一个统一的XML布局张贴在这里，但是当我试图用的setContentView加载它的应用程序崩溃。调试后我发现，它说：源无法找到。我已经重建了R档但这并不能帮助。仅供参考我的课堂延伸GLSurfaceView被称为GLView。任何帮助将是AP preciated。

 包org.kizik.WLTBO;
    进口android.app.Activity;
    进口android.os.Bundle;
    进口android.view.View;
    进口android.view.ViewGroup;
    进口android.widget.FrameLayout;
    进口android.widget.LinearLayout;
    进口android.widget.RelativeLayout;
    进口android.widget.TextView;
    公共类WholettheballoutActivity延伸活动{
       GLView图。       @覆盖
       公共无效的onCreate（捆绑savedInstanceState）{
          super.onCreate（savedInstanceState）;
          的setContentView（R.layout.score）;
          鉴于=（GLView）findViewById（R.id.mySurfaceView）;       //可以使用的FrameLayout举行表面观
          / *的FrameLayout的FrameLayout =新的FrameLayout（本）;
          frameLayout.addView（视图）;          //然后创建一个布局来容纳一切，例如RelativeLayout的
          的RelativeLayout的RelativeLayout =新的RelativeLayout（本）;
          relativeLayout.addView（的FrameLayout）;
          relativeLayout.addView（评分）;
          的setContentView（RelativeLayout的）; * /
       }       @覆盖
       保护无效的onPause（）{
           super.onPause（）;
           view.onPause（）;
       }       @覆盖
       保护无效onResume（）{
           super.onResume（）;
           view.onResume（）;
       }
    }
 

通过XML文件名score.xml

 ＆LT;？XML版本=1.0编码=UTF-8＆GT？;
＆LT; LinearLayout中的xmlns：机器人=htt​​p://schemas.android.com/apk/res/android
    机器人：方向=垂直
    机器人：layout_width =FILL_PARENT
    机器人：layout_height =FILL_PARENT＆GT;    ＆LT; TextView的机器人：ID =@ + ID / textView1
        机器人：layout_width =FILL_PARENT
        机器人：layout_height =WRAP_CONTENT/＆GT;    ＆LT; TextView的机器人：ID =@ + ID / textView2
        机器人：layout_width =FILL_PARENT
        机器人：layout_height =WRAP_CONTENT/＆GT;    ＆LT; org.kizik.WLTBO.GLView
        机器人：ID =@ + ID / mySurfaceView
        机器人：layout_width =FILL_PARENT
        机器人：layout_height =WRAP_CONTENT
        机器人：layout_weight =1/＆GT;＆LT; / LinearLayout中＆GT;
 

解决方案

如果您已经创建了一个参数GLView（上下文C）的构造可能发生，你需要创建一个这样GLView另一个构造（上下文C，AttributeSet中的ATTRS ），所以如果u还没有创建的构造函数，那么就不能不是由类找到GLView，怎么不创建它的构造.. !!我想你还没有创建的构造.. !!

 公共GLview（上下文的背景下，ATTRS的AttributeSet）{   超（背景下，ATTRS）; }
 

I am trying to have a custom GLSurfaceView with some text over it, to display the score in a game. I have made a uniform xml layout based off of someones post here but when I try to load it with a setContentView the app crashes. after debugging I found that it says "Source can not be found". I have rebuilt the R file but that doesn't help. For reference my class that extends GLSurfaceView is called GLView. Any help would be appreciated.

 package org.kizik.WLTBO;


    import android.app.Activity;
    import android.os.Bundle;




    import android.view.View;
    import android.view.ViewGroup;
    import android.widget.FrameLayout;
    import android.widget.LinearLayout;
    import android.widget.RelativeLayout;
    import android.widget.TextView;


    public class WholettheballoutActivity extends Activity {
       GLView view;



       @Override
       public void onCreate(Bundle savedInstanceState) {
          super.onCreate(savedInstanceState);
          setContentView(R.layout.score);
          view = (GLView) findViewById(R.id.mySurfaceView);

       // You can use a FrameLayout to hold the surface view
          /*FrameLayout frameLayout = new FrameLayout(this);
          frameLayout.addView(view);

          // Then create a layout to hold everything, for example a RelativeLayout
          RelativeLayout relativeLayout= new RelativeLayout(this);
          relativeLayout.addView(frameLayout);
          relativeLayout.addView(score);
          setContentView(relativeLayout);*/
       }

       @Override
       protected void onPause() {
           super.onPause();
           view.onPause();
       }

       @Override
       protected void onResume() {
           super.onResume();
           view.onResume();
       }
    }

With the XML file name score.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent" >

    <TextView android:id="@+id/textView1"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"/>

    <TextView android:id="@+id/textView2"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"/>

    <org.kizik.WLTBO.GLView
        android:id="@+id/mySurfaceView"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:layout_weight="1"/>        

</LinearLayout>

解决方案

It may happen if you have created a constructor with single parameter GLView(Context c) , you need to create another constructor like this GLView(Context c, AttributeSet attrs), so if u havent created that constructor, then it can not not find the GLView from class, coz its constructor is not created..!! i think you havent created that constructor..!!

 public GLview(Context context, AttributeSet attrs){

   super(context,attrs); }

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