检测是否在按键事件之外按下了按键 [英] Detecting if a key is pressed outside the key events

问题描述

我想检测在程序启动期间是否按住了某个键，即在static void Main()中

这有可能实现吗?我想创建一个安全模式，如果用户在启动程序时按住Shift键，则会进入此模式.

I want to detect if a key is held down during the start up of my program, i.e. in static void Main()

Is this possible to achieve? I want to make a safe mode that will be entered if the user holds down the shift key when starting the program.

推荐答案

前一段时间，我发现解决方案仅可用于PInvoke.特别是，我用了这个:

A while ago, I found that a comprehensive solution is only possible used PInvoke. In particular, I used this:

const string dllName = "user32.dll";
[DllImport(dllName, EntryPoint = "GetKeyboardState")]
static extern void PInvokeGetKeyboardState(KeyStateValue[] lpKeyState);

WIN API GetKeyboardState检索每个虚拟键的状态，而不仅仅是修饰键(可通过System.Windows.Forms访问)；可以将Control，Alt和Shift键的左，右变体视为不同.
此外，此配方对WPF和System.Windows.Forms均适用.

不幸的是，使用PInvoke是不兼容的:GetKeyboardState仅在Windows平台上有效.

WIN API GetKeyboardState retrieves status of every virtual key, not just modifier keys (accessible with System.Windows.Forms); left and right variants of Control, Alt and Shift keys can be treated as different.
Also, this recipe works for both WPF and System.Windows.Forms.

Unfortunately, using PInvoke is incompatible: GetKeyboardState works only on Windows platform.

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